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postnew [5]
3 years ago
15

Answer fast please and thanks!

Mathematics
2 answers:
Stella [2.4K]3 years ago
8 0

Answer:

tan 30 = x / 15

General Formulas and Concepts:

<u>Trigonometry</u>

  • [Right Triangles Only] SOHCAHTOA
  • [Right Triangles Only] tanθ = opposite over adjacent

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify variables</em>

Angle θ = 30°

Opposite Leg = <em>x</em>

Adjacent Leg = 15

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Substitute in variables [tangent]:                                                                     tan 30 = x / 15

arlik [135]3 years ago
7 0

Answer:

3rd one

Step-by-step explanation:

Recall that

Sin = opposite over hypotenuse

Cos = adjacent over hypotenuse

Tan = opposite over adjacent

For the angle with a measure of 30 degrees we are given it's adjacent side length and need to find it's opposite side length

When dealing with opposite and adjacent we use tangent

If tan = opposite over adjacent

Then tan30 = x / 15 and the correct answer choice is the third one

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Natasha_Volkova [10]


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6 0
3 years ago
How is 1/2 and 4/8 equivalent​
alexandr402 [8]

Answer:

they are both half

Step-by-step explanation:

1 is half of 2 And 4 is half of 8

5 0
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PLZ HELP ME I DO NOT UNDERSTAND
tekilochka [14]

Answer:

b is the answer

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
"Mindy has a piece of string that is 5 1/2yd long. She cuts it into pieces that are each 1/2 yd long. Solve the equation 5 1/2 =
Debora [2.8K]

Answer:

Step-by-step explanation:

Mindy has a piece of string that is 5 1/2yd long. She cuts it into pieces that are each 1/2 yd long. Solve the equation 5 1/2 = 1/2x to find out how many pieces of string, x, she gets. Show your work

6 0
2 years ago
3^x= 3*2^x solve this equation​
kompoz [17]

In the equation

3^x = 3\cdot 2^x

divide both sides by 2^x to get

\dfrac{3^x}{2^x} = 3 \cdot \dfrac{2^x}{2^x} \\\\ \implies \left(\dfrac32\right)^x = 3

Take the base-3/2 logarithm of both sides:

\log_{3/2}\left(\dfrac32\right)^x = \log_{3/2}(3) \\\\ \implies x \log_{3/2}\left(\dfrac 32\right) = \log_{3/2}(3) \\\\ \implies \boxed{x = \log_{3/2}(3)}

Alternatively, you can divide both sides by 3^x:

\dfrac{3^x}{3^x} = \dfrac{3\cdot 2^x}{3^x} \\\\ \implies 1 = 3 \cdot\left(\dfrac23\right)^x \\\\ \implies \left(\dfrac23\right)^x = \dfrac13

Then take the base-2/3 logarith of both sides to get

\log_{2/3}\left(2/3\right)^x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x \log_{2/3}\left(\dfrac23\right) = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(3^{-1}\right) \\\\ \implies \boxed{x = -\log_{2/3}(3)}

(Both answers are equivalent)

8 0
2 years ago
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