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3 years ago

Answer fast please and thanks!

Mathematics

2 answers:

Stella [2.4K]3 years ago

8 0

Answer:

tan 30 = x / 15

General Formulas and Concepts:

Trigonometry

[Right Triangles Only] SOHCAHTOA
[Right Triangles Only] tanθ = opposite over adjacent

Step-by-step explanation:

Step 1: Define

Identify variables

Angle θ = 30°

Opposite Leg = x

Adjacent Leg = 15

Step 2: Solve for x

Substitute in variables [tangent]: tan 30 = x / 15

arlik [135]3 years ago

7 0

Answer:

3rd one

Step-by-step explanation:

Recall that

Sin = opposite over hypotenuse

Cos = adjacent over hypotenuse

Tan = opposite over adjacent

For the angle with a measure of 30 degrees we are given it's adjacent side length and need to find it's opposite side length

When dealing with opposite and adjacent we use tangent

If tan = opposite over adjacent

Then tan30 = x / 15 and the correct answer choice is the third one

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2 years ago

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kompoz [17]

In the equation

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divide both sides by $2^x$ to get

$\dfrac{3^x}{2^x} = 3 \cdot \dfrac{2^x}{2^x} \\\\ \implies \left(\dfrac32\right)^x = 3$

Take the base-3/2 logarithm of both sides:

$\log_{3/2}\left(\dfrac32\right)^x = \log_{3/2}(3) \\\\ \implies x \log_{3/2}\left(\dfrac 32\right) = \log_{3/2}(3) \\\\ \implies \boxed{x = \log_{3/2}(3)}$

Alternatively, you can divide both sides by $3^x$ :

$\dfrac{3^x}{3^x} = \dfrac{3\cdot 2^x}{3^x} \\\\ \implies 1 = 3 \cdot\left(\dfrac23\right)^x \\\\ \implies \left(\dfrac23\right)^x = \dfrac13$

Then take the base-2/3 logarith of both sides to get

$\log_{2/3}\left(2/3\right)^x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x \log_{2/3}\left(\dfrac23\right) = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(3^{-1}\right) \\\\ \implies \boxed{x = -\log_{2/3}(3)}$

(Both answers are equivalent)

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