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3 years ago

Can you answer this math homework? Please!

Mathematics

2 answers:

Levart [38]3 years ago

8 0

Answer:

They are both correct

Step-by-step explanation:

They started isolating different variables but essentially they have found the same answers just with different isolated variables, thus their answers look different, but in reality, are the exact same.

We can test by plugging 5 in for x, and 15 in for y.

Jared:

$y=x+10\\$
$15=5+10$
$15=15$

Nicole:

$x=y-10$
$5=15-10$
$5=5$

Equations are equal.

Nuetrik [128]3 years ago

5 0

Answer:

Step-by-step explanation:

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Explain how to find the number of comic book:<br>you could buy with $25.00.

xenn [34]

Answer:

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3 years ago

You are designing a rectangular poster to contain 7575 in2 of printing with a 33-in margin at the top and bottom and a 11-in m

erma4kov [3.2K]

Answer:

The dimensions of the rectangular poster is 15 in by 5 in.

Step-by-step explanation:

Given that, the area of the rectangular poster is 75 in².

Let the length of the rectangular poster be x and the width of the rectangular poster be y.

The area of the poster = xy in².

$\therefore xy=75$

$\Rightarrow y=\frac{75}{x}$ ....(1)

1 in margin at each sides and 3 in margin at top and bottom.

Then the length of printing space is= (x-2.3) in

=(x-6) in

The width of printing space is = (y-2.1) in

=(y-2) in

The area of the printing space is A =(x-6)(y-2) in²

∴ A =(x-6)(y-2)

Putting the value of y

$\Rightarrow A =(x-6)(\frac{75}{x}-2)$

$\Rightarrow A = 87-\frac{450}{x}-2x$

Differentiating with respect to x

$A '= \frac{450}{x^2}-2$

Again differentiating with respect to x

$A''=-\frac{900}{x^3}$

To find the minimum area of printing space, we set A' = 0

$\therefore \frac{450}{x^2}-2=0$

$\Rightarrow 450 =2x^2$

$\Rightarrow x^2=225$

$\Rightarrow x=\pm 15$

Now putting x=±15 in A''

$A''|_{x=15}=-\frac{900}{15^3}$

$A''|_{x=-15}=-\frac{900}{(-15)^3}=\frac{900}{(15)^3}>0$

Since at x=15 , A"<0 Therefore at x=15 , the area will be minimize.

From (1) we get

$y=\frac{75}{x}$

Putting the value of x

$y=\frac{75}{15}$

=5 in

The dimensions of the rectangular poster is 15 in by 5 in.

4 0

3 years ago

Sidney is making greeting cards, which she will sell by the box at an arts fair. She paid $32 for a booth at the fair, and the m

borishaifa [10]

So think of it like this she starts off $32 negative and subtract 3 from each box of cards she makes . So each box of cards she will make $8 that being said

32/8 =4 (it will take 4 box of cards to pay off her booth expense).

Sales would be 11x 4 =44

Expenditures would be 3x4 =32 (the amount used to make cards ) +32(the amount paid for the booth)

Which in total would be $64

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3 years ago

Help needed asap will give brainliest <3

KatRina [158]

Answer:

The answer is,surface area= ✓<u>416</u>

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3 years ago