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3 years ago

M=2 (-1, -4) slope intersect form

Mathematics

1 answer:

aalyn [17]3 years ago

8 0

$y=mx+b\\\\
-4=2\cdot(-1)+b\\
-4=-2+b\\
b=-2\\\\
\boxed{y=2x-2}$

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4 years ago

19. Evaluate: 5 x (8-4) ÷ 4 - 2

leva [86]

Answer:

Step-by-step explanation:

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3 years ago

what will be the total paid on an amortized loan of $15,000 for 5 years at 2 3/4% compounded monthly?

Alex73 [517]

the loan is being amortized, so that doesn't matter for its future value, the simple case that the borrower is paying it in bits monthly.

so, we're really just looking for the future value of the Principal $15000, let's convert theat mixed fraction to improper fraction, and then to a percent format firstly.

$\bf \stackrel{mixed}{2\frac{3}{4}}\implies \cfrac{2\cdot 4+3}{4}\implies \stackrel{improper}{\cfrac{11}{4}}\implies \stackrel{decimal}{2.75} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt}$

$\bf \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$15000\\ r=rate\to 2.75\%\to \frac{2.75}{100}\dotfill &0.0275\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve} \end{array}\dotfill &12\\ t=years\dotfill &5 \end{cases} \\\\\\ A=15000\left(1+\frac{0.0275}{12}\right)^{12\cdot 5}\implies A=15000\left( \frac{4811}{4800} \right)^{60}\implies A\approx 17208.318305$

how did we get 4811/4800? well, is really just the 1+(0.0275/12), which gives us about 1.0022917 but is a repeating decimal, so 4811/4800 is just the fraction version of it.

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3 years ago

What is the value of x in the equation:<br><br> -10x -19 = 19 -8x

Rom4ik [11]

Answer:

x = -19

Step-by-step explanation:

-10x - 19 = 19 - 8x

-10x + 8x = 19 + 19

-2x = 38

x = -19

6 0

3 years ago

Read 2 more answers

Anybody know the correct answer?

earnstyle [38]

Since $\csc^2{x}=\frac{1}{\sin^2{x}}$ and $\cot^2{x}=\frac{\cos^2{x}}{\sin^2{x}}$ , we can rewrite the right side of the equation as

$\frac{1}{\sin^2{x}}-\frac{\cos^2{x}}{\sin^2{x}} =\frac{1-\cos^2{x}}{\sin^2{x}}$

Using the identity $\sin^2{x}+\cos^2{x}=1$ , we can subtract $\cos^2{x}$ from either side to obtain the identity $\sin^2{x}=1-\cos^2{x}$

substituting that into our previous expression, the right side of our equation simply becomes

$\frac{\sin^2{x}}{\sin^2{x}}=1$

We can now write our whole equation as

$3\tan^2{x}-2=1$

Adding 2 to both sides:

$3\tan^2{x}=3$

dividing both sides by 3:

$\tan^2{x}=1$

$\tan{x}=\pm1$

When 0 ≤ x ≤ π, tan x can only be equal to 1 when sin x = cos x, which happens at x = π/4, and it can only be equal to -1 when -sin x = cos x, which happens at x = 3π/4

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3 years ago