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Mashcka [7]
2 years ago
13

The probability that an individual has​ 20-20 vision is 0.18. In a class of 12 ​students, what is the probability of finding fiv

e people with​ 20-20 vision?
0.417 or 0.185 or 0.18 or 0.037
Mathematics
1 answer:
Contact [7]2 years ago
5 0

Answer:

0.417

Step-by-step explanation:

Just divide 12/5 and the answer is 0.416666666...

Round up and you get 0.417.

<em>Hope this helped! </em>

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What is the volume of a cone that has a radius of 4 cm and a height of 9 cm?
vodka [1.7K]
For any sort of pyramid or cone, the volume is 1/3 of the volume of a prism with the same base and height. Since the volume of a prism/cylinder is V=Bh, the volume of a pyramid/cone is V=\frac{1}3Bh.

In this case, our base is a circle, which has a radius of 4 cm.
The area of a circle is A=\pi r^2 where r is the radius.
A=\pi (4)^2=\pi (4\times4)=16\pi=B

We now know that our base is 16π cm.
We also know that our height is 9 cm.
Let's plug these into our volume formula.

V=\frac{1}3\times16\pi \times9

Use 3.14 to approximate pi as the question states. 16 × 3.14 = 50.24.

V\approx\frac{1}3\times50.24\times9

We could punch all of that into our calculator to get the same answer, but since 1/3 of 9 is clearly 3, let's just go with that.

V\approx3\times50.24

\boxed{V\approx150.72\ cm^3}
8 0
3 years ago
Read 2 more answers
A small town has 2000 families. The average number of children per family is mu = 2.5, with a standard deviation sigma = 1.7. A
Nikitich [7]

Answer:

Let X the random variable that represent the number of children per fammili of a population, and for this case we know the following info:

Where \mu=2.5 and \sigma=1.7

We select a sample of n =64 >30 and we can apply the central limit theorem. From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And for this case the standard error would be:

\sigma_{\bar X} = \frac{1.7}{\sqrt{64}}= 0.2125

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

Let X the random variable that represent the number of children per fammili of a population, and for this case we know the following info:

Where \mu=2.5 and \sigma=1.7

We select a sample of n =64 >30 and we can apply the central limit theorem. From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And for this case the standard error would be:

\sigma_{\bar X} = \frac{1.7}{\sqrt{64}}= 0.2125

6 0
3 years ago
What is the period of y=4cos5x
kvasek [131]

you take 2pi and divide it by bits stolen from the equation its explained more in the screennshot

5 0
2 years ago
It takes machine A x hours to manufacture a deck of cards that machine B can manufacture in y hours. If machine A operates alone
nlexa [21]

Answer:

The expression that shows how long the two machines will operate simultaneously is:

\frac{y(100x-z)}{x+y}

Step-by-step explanation:

We know that:

x: hours to manufacture a deck of cards for machine A

y: hours to manufacture a deck of cards for machine B

z: hours that machine A operates alone

The number of decks manufactured only by machine A is:

\frac{z}{x}

So, the remaining decks are given by:

100-\frac{z}{x}=\frac{100x-z}{x}

Then, the combined rate of machines A and B would be:

\frac{1}{x} +\frac{1}{y} =\frac{x+y}{xy}

The work-rate formula is:

Amount= Rate \times Time

Hence, the time that the two machines work simultaneously is:

Time=\frac{Amount}{Rate}

Time=\frac{Amount}{Rate} =\frac{\frac{100x-z}{x} }{\frac{x+y}{xy} } ={\frac{100x-z}{x} \times \frac{xy}{x+y}=\frac{y(100x-z)}{x+y}

3 0
3 years ago
Pls Help,
faltersainse [42]

Answer:

Potato

Step-by-step explanation:

1 kg = 1000 g

Assuming the potatoes have the same mass, and the pears have the same mass, then the mass of each potato is:

1000 g / 5 = 200 g

And the mass of each pear is:

1200 g / 8 = 150 g

So a potato has more mass than a pear.

8 0
3 years ago
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