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PIT_PIT [208]
3 years ago
14

Find the length of CE

Mathematics
1 answer:
saw5 [17]3 years ago
4 0

Answer:

C. 37.8 units

Step-by-step explanation:

ED = 17/ cos(38°) = 17 / 0.7880 = 21.6 units

DF = 17× tan (38°) = 17× 0.7813 = 13.3 units

CD = 10/13.3 × 21.6 = 16.2 units

so, the length of CE = 21.6+16.2 = 37.8 units

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Yuki888 [10]
X/13 2/7
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3 years ago
What is the value of x in the equation 8 + x = 3? (4 points) −5 5 11 24
Irina18 [472]

Answer:

-5 is the correct answer

8 0
3 years ago
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A culture started with 2000 bacteria after 5 hours it grew to 2600
Jobisdone [24]
P(t) = P₀ e^(kt) 

<span>Where P₀ is the initial population, </span>
<span>P(t) is the population after "t" time. </span>
<span>t is your rate (can be hours, days, years, etc. in this case, hours) </span>
<span>k is the growth constant for this particular problem. </span>

<span>So using the information given, solve for k: </span>

<span>P₀ = 2000 </span>
<span>P(4) = 2600 </span>

<span>P(t) = P₀ e^(kt) </span>
<span>2600 = 2000e^(k * 4) </span>
<span>1.3 = e^(4k) </span>

<span>Natural log of both sides: </span>

<span>ln(1.3) = 4k </span>
<span>k = ln(1.3) / 4 </span>

<span>Now that we have a value for "k", use that, the same P₀, then solve for P(17): </span>

<span>P(t) = P₀ e^(kt) </span>
<span>P(17) = 2000 e^(17ln(1.3) / 4) </span>

<span>Using a calculator to get ln(1.3) then to simplify from there, we get: </span>

<span>P(17) ≈ 2000 e^(17 * 0.262364 / 4) </span>
<span>P(17) ≈ 2000 e^(4.460188 / 4) </span>
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3 0
3 years ago
Can someone try to help me and explain it for me
Alla [95]

Answer:

g(f(0)) = 5

Step-by-step explanation:

To evaluate g(f(0)), evaluate f(0) then substitute this value into g(x)

From the table

when x = 0, then f(0) = 1

Then

g(1)

when x = 1 , then g(x) = 5

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g(f(0)) = 5

6 0
3 years ago
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In studies for a​ medication, 3 percent of patients gained weight as a side effect. Suppose 643 patients are randomly selected.
timofeeve [1]

Part a)

It was given that 3% of patients gained weight as a side effect.

This means

p = 0.03

q = 1 - 0.03 = 0.97

The mean is

\mu  = np

\mu = 643 \times 0.03 = 19.29

The standard deviation is

\sigma =  \sqrt{npq}

\sigma =  \sqrt{643 \times 0.03 \times 0.97}

\sigma =4.33

We want to find the probability that exactly 24 patients will gain weight as side effect.

P(X=24)

We apply the Continuity Correction Factor(CCF)

P(24-0.5<X<24+0.5)=P(23.5<X<24.5)

We convert to z-scores.

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P(X≤24)

We apply the continuity correction factor to get;

P(X<24+0.5)=P(X<24.5)

We convert to z-scores to get:

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Part d)

We want to find the probability that:

between 24 and 28, inclusive, will gain weight as a side effect.

P(24≤X≤28)=

P(23.5≤X≤28.5)

Convert to z-scores:

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3 0
4 years ago
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