Answer:
625
Step-by-step explanation:
This is a reoccurring permutation
so it is 5^3
You have the following inequality:
In order to determine which are valid solutions of the previous inequality, take into account that any positive value for V is solution of the previous equation, because if V is positive, 96/V is also positive.
Then, the following area solutions:
V = 3
V = 6
V = 8
V = 4
Dependent events are events that depend on other events. Independent events happen no matter what. In conclusion the answer has to be C. in the assumption that Nia wouldnt have pulled a pencil out of the drawer for herself if she hadnt gotten one for fred
407 over 5 but it also has to be simplified
In probability, problems involving arrangements are called combinations or permutations. The difference between both is the order or repetition. If you want to arrange the letters regardless of the order and that there must be no repetition, that is combination. Otherwise, it is permutation. Therefore, the problem of arrange A, B, C, D, and E is a combination problem.
In combination, the number of ways of arranging 'r' items out of 'n' items is determined using n!/r!(n-r)!. In this case, you want to arrange all 5 letters. So, r=n=5. Therefore, 5!/5!(505)! = 5!/0!=5!/1. It is simply equal to 5! or 120 ways.
