Question

Algebra 2 PLEASE HELP

Answer 1

Answer:

$\frac{x+20}{x+4}$

Step-by-step explanation:

Can't cancel out terms like that

need to factor out the top and bottom

$\frac{x^{2} +16x-80}{x^{2} -16}$ = $\frac{(x+20)(x-4)}{(x-4)(x+4)}$   now cancel out the (x-4) from the top and bottom

= $\frac{x+20}{x+4}$

Answer 2

Answer & Explanation:

Error: individual terms in an equation in a fraction cannot be directly canceled out.

Correction:

the easy way (solve the quadratic equation in the numerator and complete the square in the denominator):

(x^2 + 16x - 80) / (x^2 - 16)

(x+20)(x-4) / (x+4)(x-4)

x+20 / x+4

the complicated way (manipulate the exponents and common factors):

(x^2 + 16x - 80) / (x^2 - 16)

(x^2 - 4x + 20x - 80) / x^2 - 2^4

x(x^2-1 - 2^2)+4*5(x - 2^4-2) / (x - 2^2)(x + 2^2)

x(x-4)+20(x-4) / (x-4)(x+4)

x(x-4)+(2^2 (5))(x-4) / (x-4)(x+4)

(x-4)(x + 2^2 (5)) / (x-4)(x+4)

(x-4)(x+20) / (x-4)(x+4)

x+20 / x+4