Answer:
(g+f)(x)=(2^x+x-3)^(1/2)
Step-by-step explanation:
Given
f(x)= 2^(x/2)
And
g(x)= √(x-3)
We have to find (g+f)(x)
In order to find (g+f)(x), both the functions are added and simplified.
So,
(g+f)(x)= √(x-3)+2^(x/2)
The power x/2 can be written as a product of x*(1/2)
(g+f)(x)= √(x-3)+(2)^(1/2*x)
We also know that square root dissolves into power ½
(g+f)(x)=(x-3)^(1/2)+(2)^(1/2*x)
We can see that power ½ is common in both functions so taking it out
(g+f)(x)=(x-3+2^x)^(1/2)
Arranging the terms
(g+f)(x)=(2^x+x-3)^(1/2) ..
Answer:
well what is the question here?
Step-by-step explanation:
Answer:
<h2>C.</h2>
Step-by-step explanation:
The equationof a circle:
<em>(h, k)</em><em> - center</em>
<em>r</em><em> - radius</em>
<em />
We have <em>center = (4, -1) → h = 4, k = -1</em>, and <em>r = 9</em>.
Substitute:
Not sure about the first one,
The second one is 1/9.
Factor the denominator
x^2+3x-10
(x+5)(x-2)
(x-2)/((x+5)(x-2))
The x-2 in the numerator and denominator cancel out.
Final answer: x+5
