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valentinak56 [21]
3 years ago
6

I dont know how to do this.

Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
5 0
The answer to the question

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ANOTHER ONE 3 HELP ME AGAIN BEFORE TIME RUNS OUT.
kramer

Answer:

the answer is parallel lines

5 0
3 years ago
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If S_1=1,S_2=8 and S_n=S_n-1+2S_n-2 whenever n≥2. Show that S_n=3⋅2n−1+2(−1)n for all n≥1.
Snezhnost [94]

You can try to show this by induction:

• According to the given closed form, we have S_1=3\times2^{1-1}+2(-1)^1=3-2=1, which agrees with the initial value <em>S</em>₁ = 1.

• Assume the closed form is correct for all <em>n</em> up to <em>n</em> = <em>k</em>. In particular, we assume

S_{k-1}=3\times2^{(k-1)-1}+2(-1)^{k-1}=3\times2^{k-2}+2(-1)^{k-1}

and

S_k=3\times2^{k-1}+2(-1)^k

We want to then use this assumption to show the closed form is correct for <em>n</em> = <em>k</em> + 1, or

S_{k+1}=3\times2^{(k+1)-1}+2(-1)^{k+1}=3\times2^k+2(-1)^{k+1}

From the given recurrence, we know

S_{k+1}=S_k+2S_{k-1}

so that

S_{k+1}=3\times2^{k-1}+2(-1)^k + 2\left(3\times2^{k-2}+2(-1)^{k-1}\right)

S_{k+1}=3\times2^{k-1}+2(-1)^k + 3\times2^{k-1}+4(-1)^{k-1}

S_{k+1}=2\times3\times2^{k-1}+(-1)^k\left(2+4(-1)^{-1}\right)

S_{k+1}=3\times2^k-2(-1)^k

S_{k+1}=3\times2^k+2(-1)(-1)^k

\boxed{S_{k+1}=3\times2^k+2(-1)^{k+1}}

which is what we needed. QED

6 0
2 years ago
Quadrilateral ABCD is rotated 145° about point T. The result is quadrilateral A'B'C'D'. Which congruency statement is correct?
lilavasa [31]
<span>The congruency statement should be that which shows the congruency of the corresponding angle and the sides. In the rotation of the polygon, the angle A is congruent with angle A' still. The same is true for all the angles and sides. The congruency statement is therefore, ABCD is congruent to A'B'C'D' The answer to this item is letter A. </span>
3 0
3 years ago
Read 2 more answers
Can I get some help please​
lys-0071 [83]

Answer:

C

Step-by-step explanation:

C is the right answer that you're looking for because the hundredth value in this number is 3 in 345 and the closest hundredth there is 300 so the number closest to hundredths is 2,684,300

7 0
3 years ago
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2root 3 x 3 root 8 fully simplified
LuckyWell [14K]

Answer:

  • 12\sqrt{6}

Step-by-step explanation:

<h3>Given expression</h3>

  • 2 \sqrt{3} *3\sqrt{8}

<h3>Simplify the expression in steps as below</h3>

  • 2 \sqrt{3} *3\sqrt{8}  =
  • 2 \sqrt{3} *3\sqrt{2^2*2} =
  • 2 \sqrt{3} *3*2\sqrt{2} =
  • 2*6* \sqrt{3} *\sqrt{2} =
  • 12* \sqrt{3*2}  =
  • 12\sqrt{6}

Used properties in solution process:

  • \sqrt{a^2} =a
  • \sqrt{a}\sqrt{b}  =\sqrt{ab}
8 0
2 years ago
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