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pishuonlain [190]
2 years ago
6

Xo 1 2 2 4 B. 3 8 4 16 5 32

Mathematics
1 answer:
ozzi2 years ago
8 0

Answer:

What

Step-by-step explanation:

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How do you solve each system of equations?
stiv31 [10]

Answer:

x=1,y=3,z=1

Step-by-step explanation:

4x-4y+4z=-4

4x=-4+4y-4z

x=-1+y-z

Substitute  x=-1+y-z into second equation:

4\left(-1+y-z\right)+y-2z=5

-4+4y-4z+y-2z=5

5y-6z-4=5

y=\frac{6z+9}{5}

Substitute x=-1+y-z and y=\frac{6z+9}{5} into the third equation:

\frac{-41z-54}{5}+3=-16

-41z-54=-95

z=1

Substitute z=1 into y=\frac{6z+9}{5}:

y=3

Plug in y and z values into x=-1+y-z:

x=1

4 0
3 years ago
Find the probability of selecting a day that starts with the letter T
Rasek [7]

Answer:

Number of days starting from T are:-

Tuesday

Thursday

So, number = 2

Number of days in a week = 7

So, probability = 2/7

Hope it helps...!!!

Step-by-step explanation:

5 0
2 years ago
How can you tell if the solution is one value,all real numbers,or no solutions
zysi [14]
One value: would be a single valued function, or just one answer.

Real numbers would be: natural numbers, whole numbers, integers, rational numbers (fractions and repeating or terminating decimals), and irrational numbers.

No solution: there is no answer to the question.
8 0
3 years ago
There are 5 pens in a container on your desk. Among them, 3 will write well but 2 have defective ink cartridges. You will select
Norma-Jean [14]

Answer:

Kindly check explanation

Step-by-step explanation:

Total Number of pens = 5

Number of defective pens = 2

Number of non-defective pens = 3

A.) number of defective pens selected :

X : {0, 1, 2}

It is possible that no defective pen will be selected ; 1 defective will be chosen or both pens are defective.

2.)

Defective as Success (since selecting a defective pen is the point of interest.

3.)

Since selection is done without replacement

Probability of success per selection is different for each selection ;

Number of defective = 2

Number of observations = 5

P(success on first selection) = 2/5

P(success on second selection) = 1/4

Hence, X is not well approximated by a binomial random variable.

4.) if selection is done with replacement ; then then the probability of success per selection will be the Same for each selection made. Hence, X will be well approximated by a binomial Random variable.

5.) If sampling is done without replacement, then the the hypergeometric function will be a more effective approximation.

7 0
2 years ago
12 dogs decreased by 25%
il63 [147K]
The answer would be 8 dogs.

6 0
3 years ago
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