Answer:
8x+3y+6=0
transfer 8x and 6 to the equal side which becomes
3y=-8×-6
The question can't be answered with the information given.
First of all, we don't know how fast the rain is falling ... how many inches
per hour.
But even of we knew that, that would only tell us how much water would
pile up in our yard or on our street. You're talking about a river, and
that's a whole different ball game.
The rain that falls right here is going to flow down the river to somewhere
else. But the rain that falls up-river from us is going to flow down to where
we are, and the river is going to rise. The amount it rises depends on . . .
-- how fast the rain is falling,
-- how much area it's falling on,
-- how much forest there is in that area and how many houses and
parking lots where the ground can't soak up the water and hold it,
-- and also on how wide the river is and how fast the water can flow through it.
Answer:
If 27 fruits are picked at random, then 2% of the time, their mean weight will be greater than 466.37 grams
Step-by-step explanation:
Mean = 
Standard deviation =
We are supposed to find If 27 fruits are picked at random, then 2% of the time, their mean weight will be greater than how many grams i.e.P(X>x)=0.02
The mean weight is in the highest 2%, you want to go to a z-table and find the z-score that where the area to the left of the curve is closest to 0.98.
n = 27
Refer the z -table
P(Z>x)=2.06
So, If 27 fruits are picked at random, then 2% of the time, their mean weight will be greater than 466.37 grams
24,500
600*10=6000
6000+18,500=24,500
I would be happy to help!
First you need to find the total amount of trees by adding up all of the different trees:
420+160+300=880
Next you need to divide the amount of oak trees by the amount of trees in the woods:
160÷880=0.182 (rounded)
Finally to find the precentage we need to multiply the 0.182 by 100 to get the precentage of 18.2% oak trees.
