3 years ago

For this problem what is the y- intercept of the line given?

Mathematics

1 answer:

aniked [119]3 years ago

7 0

Answer:

the y intercept is 5

Step-by-step explanation:

because it says +5 at the end so this is where the line cuts the axis

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At the movie theatre, child admission is $5.40 and adult admission is $9.60 . on saturday, four times as many adult tickets as c

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What situation should be used to rewrite 16(x^3+1)^2 -22(x^3+1)-3=0 as a quadratic equation

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$16(x^3+1)^2-22(x^3+1)-3=0$

Use substitution: $x^3+1=t$

$16t^2-22t-3=0\\\\16t^2-24t+2t-3=0\\\\8t(2t-3)+1(2t-3)=0\\\\(2t-3)(8t+1)=0\iff2t-3=0\ \vee\ 8t+1=0$

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we're going back to substitution:

$x^3+1=\dfrac{3}{2}\ \vee\ x^3+1=-\dfrac{1}{8}\ \ \ \ |subtract\ 1\ from\ both\ sides\ of\ the\ equations\\\\x^3=\dfrac{1}{2}\ \vee\ x^3=-\dfrac{9}{8}\\\\x=\sqrt[3]{\dfrac{1}{2}}\ \vee\ x=\sqrt[3]{-\dfrac{9}{8}}$

$x=\dfrac{1}{\sqrt[3]2}\ \vee\ x=-\dfrac{\sqrt[3]9}{2}\\\\\boxed{x=\dfrac{\sqrt[3]4}{2}\ \vee\ x=-\dfrac{\sqrt[3]9}{2}}$

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