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Anna35 [415]
3 years ago
8

-3x + 40 = -23 A) -21 B)5.6 C)21 D)-32.3

Mathematics
1 answer:
poizon [28]3 years ago
8 0

Answer:

C) 21

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

Step-by-step explanation:

<u>Step 1: Define</u>

-3x + 40 = -23

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Isolate <em>x</em> term:                    -3x = -63
  2. Isolate <em>x</em>:                             x = 21

<u>Step 3: Check</u>

<em>Plug in x into the original equation to verify it's a solution.</em>

  1. Substitute in <em>x</em>:                    -3(21) + 40 = -23
  2. Multiply:                               -63 + 40 = -23
  3. Add:                                     -23 = -23

Here we see that -23 does indeed equal -23.

∴ x = 21 is the solution to the equation.

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Answer:

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- You want to find out the probability that that grade which is greater than 72 is also greater than 84

- Expect the answer to be 0.7143

- The explanation/steps is given below

- The answer seems (and is) reasonable. You only created a new lower limit.

Step-by-step explanation:

Distribution Type: Normal

Mean: 78

Standard deviation: 36

Range of marks: [78 - 36], [78 + 36]  = [42 to 114]

If you know that a student's grade is greater than 72, what is the probability that it's greater than 84?

In this case, the full probability level is between 72 and the upper limit of 114 (instead of between 42 and 114). First, find the fraction of this probability.

[114 - 72] ÷ [114 - 42]  = 42/72  = 0.5833

So, the probability of a student's mark falling between 72 and 114 is 0.5833.

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What fraction of this interval of 42 will bear marks between 84 and 114?

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Because of the first part of the question "If you know (are sure) that a student's grade is greater than 72...", your answer stops at 0.7143, since 72 was used as the lower limit.

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3 years ago
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