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andre [41]
3 years ago
11

Please help. If this isn't done by today i'm grounded :(

Mathematics
1 answer:
gladu [14]3 years ago
6 0

Answer:

permeant

Step-by-step explanation:

Stroking with one pole of a permanent magnet works because it aligns the atoms in the nail to line up in the same polar direction, giving the nail a north and a south magnetic pole.

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+
dmitriy555 [2]

Answer:

+ + + + += + + + + +

Step-by-step explanation:

DUH        

I mean I think I'm right

8 0
3 years ago
Let​ T: set of real numbers R Superscript nℝnright arrow→set of real numbers R Superscript mℝm be a linear​ transformation, and
Klio2033 [76]

Answer:

\{T(v_1), T(v_2), T(v_3)\} is linearly dependent set.

Step-by-step explanation:

Given:  \{v_1,v_2,v_3\} is a linearly dependent set in set of real numbers R

To show: the set \{T(v_1), T(v_2), T(v_3)\} is linearly dependent.

Solution:

If \{v_1,v_2,v_3,...,v_n\} is a set of linearly dependent vectors then there exists atleast one k_i:i=1,2,3,...,n such that k_1v_1+k_2v_2+k_3v_3+...+k_nv_n=0

Consider k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0

A linear transformation T: U→V satisfies the following properties:

1. T(u_1+u_2)=T(u_1)+T(u_2)

2. T(au)=aT(u)

Here, u,u_1,u_2∈ U

As T is a linear transformation,

k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0\\T(k_1v_1)+T(k_2v_2)+T(k_3v_3)=0\\T(k_1v_1+k_2v_2+k_3v_3)=0\\

As \{v_1,v_2,v_3\} is a linearly dependent set,

k_1v_1+k_2v_2+k_3v_3=0 for some k_i\neq 0:i=1,2,3

So, for some k_i\neq 0:i=1,2,3

k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0

Therefore, set \{T(v_1), T(v_2), T(v_3)\} is linearly dependent.

6 0
3 years ago
Evan earns $18 per hour. how much will he earn per hour if he gets a 5% raise?
agasfer [191]
18·0.05= 0.9
0.9+18= 18.90
Even will earn $18.90 dollars an hour.
6 0
3 years ago
How do I answer this?​
Stels [109]
If you are trying to find the area the answer would be 48
3 0
3 years ago
Any assistance would be great!
vladimir1956 [14]

The domain is the input values, which would also be X values.

{ x |x= -5, -3, 1, 2,6}

4 0
3 years ago
Read 2 more answers
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