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muminat
3 years ago
10

How do I solve -12+1/2x=-6​

Mathematics
1 answer:
dedylja [7]3 years ago
6 0

Answer:

x = 12

Step-by-step explanation:

First, eliminate the fractional coefficient 1/2, by multiplying all three terms by 2:

-24 + x = -12

Adding 24 to both sides isolates x:  x = -12 + 24, or x = 12

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you work as a residential painter.a customer wants two table and eight chairs painted using one coat of the same color paint. ea
Lilit [14]
So 1 5/8 + 2/3 = 13/8 + 2/3
convert the fractions to a common denominator
39/24 + 16/24
55/24
=2 7/24 quarts of paint
5 0
3 years ago
kyle is thinking of a number greater than -6 2/3 and less than -6 1/2. which number could be kyle's number
vazorg [7]
The number is greater than - 6  2/3  and less than - 6 1/2.

We focus on the 2/3 and 1/2

Since it is a negative number we think of a fraction less than 2/3 and greater than 1/2, because of the negatives.

2/3 is around 0.66,  1/2 is = 0.5,  Example is 0.6 = 6/10 = 3/5

A number that fits is -6  3/5.

Check:
- 6  2/3 ≈ -6.66
-6  3/5 = - 6.60
-6  1/2  = -6.50

-6.60 is greater than -6.66, and less than -6.50
5 0
3 years ago
Read 2 more answers
If a triangle is a right triangle then the other two angles must be acute true or false ?
kolezko [41]

Answer:

The sum of the angles in any triangle is 180 degrees. If one of the three angles is 90 degrees (a right angle) the the sum of the other two angles is 90 degrees. Therefore each of the other two angles must be acute.

The statement is TRUE.

Step-by-step explanation:


8 0
3 years ago
Assume that θ is an acute angle in a right triangle satisfying the given conditions. Evaluate the 5 remaining trigonometric func
neonofarm [45]

Answer: See step by step. Replace the x with theta

Step-by-step explanation: Since sin is less than zero, and secant is positive. This means the trig values are in Quadrant 4.

We know that secФ=17/15. We need to find sin,cos,tan,csc, and cot.

We can find tangent by using the identity

tan^{2} (x)+ 1=sec^{2} (x) where x is theta.

tan^{2} (x)+1=\frac{289}{225}

tan^{2} (x)+\frac{225}{225} =\frac{289}{225}

tan^{2}(x)=\frac{64}{225}

tan x=\frac{8}{15}, Tangent in the fourth  quadrant is negative  so  the answer is instead

tan x= -\frac{8}{15}

We can find cotangent by taking the recipocial of tan so

cot=-\frac{15}{8}

We can find cos by taking reciprocal of sec remeber that cosine is positive in 4th quadrant so the answer is

cos =\frac{15}{17}

We can find sin by doing quoteint identies.

\frac{sin x}{cos x} =tan x

\frac{ sin x}{15/17} =-\frac{8}{15}

sin x= -\frac{8}{17}

To find csc, take reciprocal of sine.

csc=\frac{-17}{8}

7 0
3 years ago
Simplify the expression (2x^2+6x−7)−(3x^2+3x−1)+(x−8)​
Mademuasel [1]

Answer:

= - x^2 + 4x  - 14

Step-by-step explanation:

(2x^2+6x−7)−(3x^2+3x−1)+(x−8)​

= (2x^2+6x−7   )    −3x^2   -3x  +1     +   (x−8)​

= (2x^2+6x−7   )    −3x^2   -3x  +1     +   x−8​

= (2x^2+6x−7   )    −3x^2   -2x - 7

= 2x^2+6x−7       −3x^2   -2x - 7

= 2x^2+6x−7       −3x^2   -2x - 7

= - x^2 + 4x  - 14

8 0
3 years ago
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