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muminat
2 years ago
10

How do I solve -12+1/2x=-6​

Mathematics
1 answer:
dedylja [7]2 years ago
6 0

Answer:

x = 12

Step-by-step explanation:

First, eliminate the fractional coefficient 1/2, by multiplying all three terms by 2:

-24 + x = -12

Adding 24 to both sides isolates x:  x = -12 + 24, or x = 12

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pentagon [3]

Answer:

-3/5

Step-by-step explanation:

3 0
2 years ago
Determine whether QRS is a right triangle for the given vertices. Explain.
LekaFEV [45]

Answer:

B

Step-by-step explanation:

6 0
3 years ago
Can someone please explain?
AlladinOne [14]
<h2>Hello!</h2>

The answer is:

The correct option is the first option:  

y=-4x+64

<h2>Why?</h2>

To write the equation of the line in slope-interception  form we need to extract all the information that we need from the graphic.

We must remember that the slope-interception form of the lines is:

y=mx+b

Where,

y, is the function

m, is the slope of the line

x, is the variable

b, is the y-axis intercept

We can find the slope using the following formula:

m=\frac{ChangeInY}{ChangeInX}

Which is for this case:

m=\frac{64}{16}=4

As we can see from the graphic, the line is decresing, so the sign of the slope "m" will be negative, so:

m=-4

We can find the value of "b" seeing where the line intercepts the y-axis.

As we can see it intercept the y-axis at:  y=64

Then, now that we already know the value of "m" and "b", we can write the equation of the line:

y=mx+b=-4x+64\\y=-4x+64

So, the correct option is the first option:

y=-4x+64

Have a nice day!

4 0
2 years ago
A baseball is hit and its height is given by h = 29.4t – 4. 9t^2, where h is the
ioda

Answer:

44.1m

Step-by-step explanation:

we are given a quadratic function which represents the height and time of a baseball

\displaystyle h = 29.4t - 4.9 {t}^{2}

we want to figure out maximum height of

the baseball

since the given function is a quadratic function so we have a parabola

which means figuring out the maximum height is the same thing as figuring out the maximum y coordinate (vertex)

to do so we can use some special formulas

recall that,

\displaystyle \rm t= \frac{ - b}{  2a}

\displaystyle H_{\text{max}}=f(t)

notice that, our given function is not in standard form i.e

\displaystyle f(x) = a {x}^{2}  + bx + c

let's make it so

\displaystyle h =  - 4.9 {t}^{2}  + 29.4t

therefore we got

our <em>a</em> is -4.9 and <em>b </em>is 29.4

so substitute:

\displaystyle\rm t=  \frac{ -( 29.4)}{  2 \cdot - 4.9}

remove parentheses and change its sign:

\displaystyle\rm t=  \frac{ -29.4}{  2 \cdot - 4.9}

simplify multiplication:

\displaystyle\rm t=  \frac{ -29.4}{  - 9.8}

simplify division:

\displaystyle  \: t  = 3

so we have figured out the time when the baseball will reach the maximum height

now we have to figure out the height

to do so

substitute the got value of time to our given function

\displaystyle H_{\text{max}}=29.4\cdot 3-4.9\cdot {3}^2

simplify square:

\displaystyle H_{\text{max}}=29.4\cdot 3-4.9\cdot 9

simplify mutilation:

\displaystyle H_{\text{max}}=88.2-44.1

simplify substraction:

\displaystyle H_{\text{max}}=44.1

hence,

the maximum height of the baseball is 44.1 metres

4 0
3 years ago
Read 2 more answers
16.4.57 Question Help A box contains eighteen $1 bills, ten $5 bills, eight $10 bills, three $20 bills, and one $100 bill You bl
Rudiy27

Answer:

$ 7.7

Step-by-step explanation:

Given,

There are 18 $1 bills, ten $5 bills, eight $10 bills, three $20 bills, and one $100 bill,

Total number of bills = 18 + 10 + 8 + 3 + 1 = 40,

\because \text{Probability}=\frac{\text{Favourable outcomes}}{\text{Total outcomes}}

Thus,

The probability of $ 1 = \frac{18}{40}

The probability of $ 5 = \frac{10}{40}

The probability of $ 10 = \frac{8}{40}

The probability of $ 20 = \frac{3}{40}

The probability of $ 100 = \frac{1}{40}

If a bill is selected randomly,

The expected value of the bill

=\frac{18}{40}\times 1+\frac{10}{40}\times 5+\frac{8}{40}\times 10+\frac{3}{40}\times 20+\frac{1}{40}\times 100

=\frac{18+50+80+60+100}{40}

=\frac{308}{40}

= $ 7.7

5 0
2 years ago
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