The answer is 3s squared over r to the 4th
it should look like a fraction with 3s squared as the numerator (on top) && r to the 4th as the denominator (on bottom)
hope this was helpful, math is my strength so post more if you need help!
There is only case if ∠c=90
then Δ ACB is right angle triangle.
(hyp)^2=(base)^2+(height)^2
(AB)^2=(15)^2+(17)^2
F(x) = a*x^2 + b*x + c; where a is not 0;
f(-2) = -11 => 4a -2b + c = -11;
f(4) = 13 => 16a +4b + c = 13;
f(6) = 29 => 36a + 6b + c = 29;
You must find a, b, c;
Y = x^2 +2x
y = 3x +20
so:
x^2 + 2x = 3x + 20
subtract 3x from both side:
x^2 +2x -3x = 20
combine like terms:
x^2 -x = 20
subtract 20 from each side:
x^2 -x -20 = 0
factor the polynomial:
(x-5) (x+4) = 0
solve for x
x = 5 and x = -4 ( 5-5 = 0 and -4 +4 = 0 )
replace x = 5 in 2nd equation: y = 3(5) +20
y = 15 +20
y = 35
replace x with -4 in same equation:
y = 3(-4) +20
y = -12 +20
y = 8
so solution is (5,35) and (-4,8)
Answer: My best guess is a, but i would look into it more.
Step-by-step explanation:
