Number of child tickets bought is 20
<h3><u>
Solution:</u></h3>
Given that It cost 5 dollars for a child ticket and 8 dollars for a adult ticket
cost of each child ticket = 5 dollars
cost of each adult ticket = 8 dollars
Let "c" be the number of child tickets bought
Let "a" be the number of adult tickets bought
Total tickets sold were 110 bringing in 820 dollars
<em>Number of child tickets bought + number of adult tickets bought = 110</em>
c + a = 110 ----- eqn 1
<em><u>Also we can frame a equation as:</u></em>
Number of child tickets bought x cost of each child ticket + number of adult tickets bought x cost of each adult ticket = 820

5c + 8a = 820 -------- eqn 2
Let us solve eqn 1 and eqn 2 to find values of "c" and "a"
From eqn 1,
a = 110 - c ------ eqn 3
Substitute eqn 3 in eqn 2
5c + 8(110 - c) = 820
5c + 880 - 8c = 820
-3c = - 60
c = 20
Therefore from eqn 3,
a = 110 - 20 = 90
a = 90
Therefore number of child tickets bought is 20
Answer:

Step-by-step explanation:
Base of the isosceles triangle = 4
Perpendicular of the triangle = 3
In an isosceles triangle , a perpendicular bisects a base equally. So, here the isosceles triangle consist of 2 right angled triangles.
In that right angled triangles,
Base = 4/2 = 2 (∵ A perpendicular divides a base into 2 equal parts. )
Perpendicular = 3
Hypotenuse = x
So , according to Pythagorean Theorem ,

Using all the values above into the formula gives :-

Answer:400 multiplied by 5 percent then later multiplied by one, Answer: 20$
Step-by-step explanation:
Answer:
c correct
Step-by-step explanation:
Hello there! x = 66.
x/6 + 4 = 15
This means that since 15 - 4 = 11, x/6 = 11.
Given the two numbers and a variable, we can multiply:
6 x 11 = 66
66/6 = 11
Therefore, x = 66
Hope this helps!