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WARRIOR [948]
3 years ago
11

Juan construyó una rampa que tiene 5 m de largo y 1 m de altura. ?Cuánto mide la distancia (d) que recorre al subir la rampa

Mathematics
1 answer:
satela [25.4K]3 years ago
7 0

Answer:

d=\sqrt{26}\ m  or  d=5.1\ m

Step-by-step explanation:

<em>The question in English is</em>

Juan built a ramp that is 5 m long and 1 m high. How much is the distance (d) he travels when he climbs the ramp?

let

x -----> the length of the ramp

y ----> the height of the ramp

d ----> the distance Juan travels when he climbs the ramp

we know that

Applying the Pythagoras Theorem

d^{2}=x^{2}+y^{2}

we have

x=5\ m

y=1\ m

substitute the given values

d^{2}=5^{2}+1^{2}

d^{2}=26

d=\sqrt{26}\ m -----> exact value

d=5.1\ m ----> approximate value

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Step-by-step explanation:

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x + x - 5 = -1   {Combine like terms}

   2x - 5 = -1 {Add 5 to both sides}

        2x  = -1 + 5

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After 2 second Pattie runs = (20+5)ft
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After 4 seconds Pattie runs = (30+5) ft
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After 6 seconds Pattie runs  = (40+5) ft
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Now Keith runs at 8 ft/sec
After 1 second Keith runs = 8 ft
After 2 second Keith runs = (8+8) ft
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After 3 second Keith runs = (16+8) ft
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After 4 second Keith runs = (24+8) ft
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After 5 second Keith runs = (32+8) ft
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After 6 second Keith runs = (40+8) ft
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