Answer: 3sqrt(2)
Step-by-step explanation:
d = sqrt[(3-0)^2 + (4-1)^2]
d = sqrt[9+9]
d = sqrt(18) = 3sqrt(2)
Answer:
12
Step-by-step explanation:
The cost for n attendees will be ...
cost = 2 + 2n
We want the cost to be, at most, 26, so we have ...
26 ≥ 2 +2n
Dividing by 2 gives ...
13 ≥ 1 + n
And subtracting 1, we find the answer:
12 ≥ n
At most, there can be 12 attendees.
You could sit down with several pencils and a whole pad of paper, and
divide Leda's mass by Europa's mass. But it's probably good enough
to provide an answer that's correct to 2 or 3 significant figures, and
there's a much easier way to do that:
Leda's mass . . . . approx. 1.094 x 10¹⁶
Europa's mass . . . . approx. 4.8 x 10²²
Leda's mass is about (1.094 x 10¹⁶) / (4.8 x 10²²) of Europa's mass.
(1.094 x 10¹⁶) / (4.8 x 10²²) = 2.28 x 10⁻⁷
Leda's mass is approx. <em>0.000 000 228</em> of Europa's mass.
D + e + f when d = 20, e = -4 and f = -2 is
20 + (-4) + (-2) = 20 - 4 - 2 = 14
Answer:
4/5
Step-by-step explanation:
just divide by 10 since that's the largest number that both numbers can equally be divisible by