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3 years ago

Triangles ABC and FED are congruent right triangles. Find the length of FE. 8 m 6 m

Mathematics

1 answer:

const2013 [10]3 years ago

4 0

Sawyer and Emily is so much scary

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Solve using elimination. -7x – 5y = -4 7x + 9y = -4

Brut [27]

-7x-5y=-47x+9y=-4

combine like terms to cross out the 7x
solve for y, to get -2
plug it back in to one of the equations and x is 2

y=-2
x=2

5 0

3 years ago

Given that rectangle LMNO with coordinates L(0,0), M(3,0), N(3,7), O(0,7), P is the midpoint of LM⎯⎯⎯, and Q is the midpoint of

Elina [12.6K]

The midpoint of a line divides the line into equal segments.

The option that proves PQ = LO is (a)

The given parameters are:

$\mathbf{L = (0,0)}$

$\mathbf{M = (3,0)}$

$\mathbf{N = (3,7)}$

$\mathbf{O = (0,7)}$

P is the midpoint of LM.

So, we have:

$\mathbf{P = \frac{LM}{2}}$

$\mathbf{P = (\frac{(0 +3}{2},\frac{0+0}{2})}$

$\mathbf{P = (\frac{3}{2},0)}$

Q is the midpoint of NO.

So, we have:

$\mathbf{Q = \frac{NO}{2}}$

$\mathbf{Q = (\frac{(3 +0}{2},\frac{7+7}{2})}$

$\mathbf{Q = (\frac{3}{2},7)}$

Distance PQ is calculated as follows:

$\mathbf{d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}$

This gives:

$\mathbf{PQ = \sqrt{(3/2 - 3/2)^2 + (0 - 7)^2}}$

$\mathbf{PQ = \sqrt{ 7^2}}$

$\mathbf{PQ = 7}$

Distance LO is calculated as follows:

$\mathbf{LO = \sqrt{(0 - 0)^2 + (0 - 7)^2}}$

$\mathbf{LO = \sqrt{ 7^2}}$

$\mathbf{LO=7}$

So, we have:

$\mathbf{PQ = 7}$

$\mathbf{LO=7}$

Thus:

$\mathbf{PQ = LO}$

Hence, the correct option is (a)

Read more about distance and midpoints at:

brainly.com/question/11231122

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2 years ago

What would be the value of x in x+5=-3x-9

9966 [12]

-3 because it shows the value right there

4 0

3 years ago

Read 2 more answers

Jamal draws a line through the points (-3,4) and (2,5). What is the slope of this line?

Kay [80]

1/5

Y2 -Y1
____
X2-X1

5-4=1 = 1
________
2- - 3 = 5

5 0

3 years ago

Juan reads 300 pages 5 days which reading rate is equivalent

katrin [286]

60 pages per day!

It is shown that One is reading 300 pages in five days so we need to find a reading rate which would be the total number of pages one reads over the number of days so the substitute does values by doing 300/5 you would get 60 pages per day

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3 years ago