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Marat540 [252]
4 years ago
5

Can you reduce 7 over 28

Mathematics
2 answers:
Svet_ta [14]4 years ago
8 0

Answer:

yes u can it would be 25%

Step-by-step explanation:

Ulleksa [173]4 years ago
7 0
7/28 =
7/(22 × 7) =
(7 ÷ 7) / ((22 × 7) ÷ 7) =
1/22 =
1/4
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2 years ago
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never [62]
X = 21, angle AGE = 98˚, and angle GHD = 98˚

Notice from the graph that angles AGE and BGH are supplementary. This means that their sum is 180˚. Therefore, to find the value of x, we must solve the equation (5x – 7) + (3x + 19) = 180

To do this, we must isolate the variable on one side by undoing the equation. We do this by first combining like terms. In this case, the variable values, and the non–variable values.

***Before doing this, make it all addition by converting – (+7) into + (–7)

So our equation is 5x + 3x + –7 + 19 = 180.

5x + 3x = 8x and –7 + 19 = 12      Now we have 8x + 12 = 180

This is a simple equation. We undo the addition by subtracting 12 from both sides:    8x + 12 – 12 = 180 – 12      8x = 168

Then, we undo the multiplication by dividing 8 by both sides:    8x ÷ 8 = 168 ÷ 8    x = 21      We can check to, as (5 • 21 – 7) + (3 • 21 + 19) = 180

Now, we can easily figure out the measurements of your angles: angle AGE = 5 • 21 – 7 = 98    So the measure of angle AGE = 98˚

Upon observing the diagram more closely, you can see that angle AGE and GHD are congruent, meaning they have the same measurements. This means that if angle AGE = 98˚, then so does angle GHD.

So, x = 21, angle AGE = 98˚, and angle GHD = 98˚

8 0
3 years ago
If (x^2 - 1) is a factor of ax^4 + bx^3 + cx^2 + dx + e, show that a + c + e = b + d = 0
alisha [4.7K]
x^2-1=x^2-1^2=(x-1)(x+1)

If x²-1 is a factor of the polynomial, both x-1 and x+1 are factors of it.

According to the remainder theorem, if a binomial x-a is a factor of a polynomial p(x), then p(a)=0.

If x-1 and x+1 are factors of the polynomial p(x)=ax⁴+bx³+cx²+dx+e, then p(1)=0 and p(-1)=0.

p(1)=a \times 1^4+b \times 1^3 + c \times 1^2+ d \times 1+e \\
p(-1)=a \times (-1)^4 + b \times (-1)^3 + c \times (-1)^2 + d \times (-1)+e \\ \\
p(1)=a+b+c+d+e \\
p(-1)=a-b+c-d+e \\ \\
p(1)=0 \\
p(-1)=0 \\ \\ \hbox{add both equations:} \\
a+b+c+d+e=0 \\
\underline{a-b+c-d+e=0} \\
2a+2c+2e=0 \\
2(a+c+e)=0 \\
a+c+e=0 \\ \\
\hbox{substitute 0 for a+c+e in the first equation:} \\
a+b+c+d+e=0 \\
(a+c+e)+b+d=0 \\
0+b+d=0 \\
b+d=0 \\ \\
\boxed{a+c+e=b+d=0} \\
\hbox{proved } \checkmark
8 0
3 years ago
In the expression -5g12 which part is the base?
Montano1993 [528]
-5 is the base of -5g in this expression
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3 years ago
Jackie's mother's sister has a son. How would that son be related to Jackie? He is Jackie's​
KATRIN_1 [288]

Answer:

he is jackies cousin

Step-by-step explanation:

7 0
3 years ago
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