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11Alexandr11 [23.1K]
3 years ago
5

Evaluate the expression 15x + 4 for x = -1 1/2​

Mathematics
1 answer:
olga_2 [115]3 years ago
5 0

Answer:

18.5

Step-by-step explanation:

First we plug in the number

-1 1/2 is the same as -1.5

Plugging this in we will have:

15(-1.5) + 4 =

-22.5 + 4 =

-18.5

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Hello love! im pretty sure it's 107.65 dollars

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How do you solve 5(r+9)−2(1−r)=1<br> need quickly
RUDIKE [14]

Answer:

r=   -6

Step-by-step explanation:

expand and get

5r+45-2+2r=1

7r+43=1

7r=1-43

7r=-42

r=-6

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2 years ago
What is the slope of the line with equation y=12x
fomenos
  <span>When you have an equation of the form y = mx + b (which you do in this case), the slope is always equal to the coefficient of x, which is m or 12 in this case. Since there is no "b" in your equation, you could say that b=0, and the line is known to cross the y axis at zero. 

In case you are interested, if the equation said y = 12 x + 3 the slope of the line would still be 12 but the line would cross the y axis at 3. If the equation said y = 12x -4, the line would have a slope of 12 and would cross the y axis at -4.</span>
5 0
3 years ago
James and Bethany Morrison are celebrating their 10th anniversary by having a reception at a local reception hall. They have bud
olga_2 [115]
To write an equation and simplify it, I'll start with this:

$4,500 = $90 + $39X Let X represent the amount of people attending the party.

Subtract 90 and both sides of the equation to make the $39X alone.

$4,410 = $39X

Divide $39 into both sides of the equation to isolate or bring X alone.

113.076923 = X

Now since we have to round down, we will do 113.
Answer: 113 people can attend the anniversary party.
3 0
3 years ago
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The value of an investment A (in dollars) after t years is given by the function A(t) = A0ekt. If it takes 10 years for an inves
Ludmilka [50]

Answer:

20 years.

Step-by-step explanation:

We have been given a formula A(t)=A_0\cdot e^{kt}, which represents the  value of an investment A (in dollars) after t years.

Substitute the given values:

\$3,000=\$1,000\cdot e^{k*10}

Let us solve for k.

\frac{\$3,000}{\$1,000}=\frac{\$1,000\cdot e^{k*10}}{\$1,000}

3=e^{k*10}

Take natural log of both sides:

\text{ln}(3)=\text{ln}(e^{k*10})

Using property \text{ln}(a^b)=b\cdot \text{ln}(a), we will get:

\text{ln}(3)=10k\cdot\text{ln}(e)

We know that \text{ln}(e)=1, so

\text{ln}(3)=10k\cdot 1

\text{ln}(3)=10k

\frac{\text{ln}(3)}{10}=\frac{10k}{10}

\frac{\text{ln}(3)}{10}=k

\$9,000=\$1,000\cdot e^{\frac{\text{ln}(3)}{10}*t}

Dividing both sides by 1000, we will get:

9=e^{\frac{\text{ln}(3)}{10}*t}

Take natural log of both sides:

\text{ln}(9)=\text{ln}(e^{\frac{\text{ln}(3)}{10}*t)

\text{ln}(9)=\frac{\text{ln}(3)}{10}*t\cdot\text{ln}(e)

\text{ln}(9)=\frac{\text{ln}(3)}{10}*t\cdot1

10*\text{ln}(9)=10*\frac{\text{ln}(3)}{10}*t

10\text{ln}(9)=\text{ln}(3)*t

10\text{ln}(3^2)=\text{ln}(3)*t

2\cdot 10\text{ln}(3)=\text{ln}(3)*t

20\text{ln}(3)=\text{ln}(3)*t

Divide both sides by \text{ln}(3):

\frac{20\text{ln}(3)}{\text{ln}(3)}=\frac{\text{ln}(3)*t}{\text{ln}(3)}

20=t

Therefore, it will take 20 years for the investment to be $9,000.

5 0
3 years ago
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