The temperature was -12 degrees
The two diagonals intersects at right-angle for a kite
the long diagonal also bisects the short diagonal so QP = PS = QS/2 = 6/2 = 3
QPR is a right-angle triangle with QR at 5 and QR at 3
RP = sqrt (5^2 - 3^) = 4m
9514 1404 393
Answer:
Step-by-step explanation:
Generally, the single variable on the left side of the equation is the "output" or dependent variable, while any other variables on the right side of the equation are considered to be independent variables, or "input."
So, we assume your first question is asking for the value of t that makes w=176. Put the values in the equation and solve for the unknown.
w = 112 +8t
176 = 112 + 8t
64 = 8t . . . . . . . subtract 112
8 = t . . . . . . . . . divide by 8
The input for an output of 176 is 8.
__
Ordered pairs are always written as ...
(input, output)
So, (4, 144) means the output is 144 for an input of 4.
When we are given 3 sides, we try to solve the angles first by using the
law of cosines
cos (A) = [b^2 + c^2 - a^2] / (2 * b * c)
cos (A) = [43^2 + 17^2 -27^2] / (2 * 43 * 17)
cos (A) = [1,849 + 289 -729] /
<span>
<span>
<span>
1,462
</span></span></span>cos (A) = 1,409 / 1,462
cos (A) =
<span>
<span>
<span>
0.96374829001368
Angle A = 15.475
Now that we have one angle, we next can use the
Law of Sines
sin(B) / side b = sin(A) / side a
sin(B) = sin(A) * sideb / sidea
</span></span></span><span>sin(B) = sin(15.475) * 43 / 27
</span><span>sin(B) = 0.26682 * 43 / 27
sin (B) = </span><span>0.424935555555</span>
Angle B = 25.147 Degrees
Remember the arc sine (<span>0.424935555555) also equals </span>
<span>
<span>
<span>
154.85
</span></span></span>Finally, calculating the third angle is quite easy
Angle C = 180 - Angle (A) - Angle(B)
Angle C = 180 - 15.475 - 154.85
Angle C = 9.675
Source:
http://www.1728.org/trigtut2.htm
