<h2>A can complete the work in 7*6 hrs = 42 hrs.
</h2><h2>
</h2><h2>A can complete in 1 hr = 1/42 part.
</h2><h2>
</h2><h2>B can complete the work in 7*8 hr = 56 hrs.
</h2><h2>
</h2><h2>A&B together do in 1 hr = 1/42 + 1/56 = 7/168 = 1/24 part. So they will do in 8 hrs = 8*1/24 = 1/3 part.
</h2><h2>
</h2><h2>Hence they need 1÷1/3 = 3 days to complete the work.</h2>
Answer: 1. Origin
2. x axis
3. X coordinate
4. Y coordinate
5. Y axis
Step-by-step explanation: Math says so but I recommend watching a video for a better explanation.
1=65 degrees
Because 5=65 and they are the same angle/degree
There might be two ways to go about this
(1) I am going to assume that we can construct a second (reference) triangle - and you confirmed that it is ok to use trigonometry on that, and then we use the relationship between areas of similar triangles to get what we want. I choose a triangle DEF with same angles, 15, 75, and 90 degrees, and the hypotenuse DE a of length 1 (that is a triangle similar to ABC). I use sin/cos to determine the side lengths: sin(15)=EF and cos(15)=DF and then compute the area(DEF) =EF*DF/2. This turns out to be 1/8 = 0.125.
Now one can use the area formula for similar triangles to figure out the area of ABC - this without trigonometry now: area(ABC)/area(DEF)=(12/1)^2
so area(ABC)=144*area(DEF)=144*0.125=18
(2) Construct the triangle ABC geometrically using compass, protractor, and a ruler. Draw a line segment AB of length 12. Using the compass draw a (Thales') semi-circle centered at the midpoint of AB with radius of 6. Then, using the protractor, draw a line at 75 degrees going from point B. The intersection with the semicircle will give you point C. Finally. draw a line from C to A, completing the triangle. Then, using ruler, measure the length BC and AC.
Calculate the area(ABC)=BC*CA/2, which should come out close to 18, if you drew precisely enough.