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lesantik [10]
3 years ago
12

Find the values ​​of x and y for the following matrix equations​

Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
3 0

Answer:

Step-by-step explanation:

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in a class of 32 students the mean height of the 14 boys is 1.56 meters and the mean height of all 32 students is 1.151 meters.
Nimfa-mama [501]

Answer: Hence, Mean height of the girls is: 1.48

Step-by-step explanation: It is given that:

in a class of 32 students .

the mean height of 14 boys is 1.56 and the mean height of all 32 students is 1.515.

Since there are 14 boys in a class.

So, number of girls is equal to (32-14)=18.

The mean height of 14 boys is 1.56.

Hence the sum of height of 14 boys is= 1.56×14=21.84

Similarly mean height of 32 students is 1.515.

Hence, sum of height of 32 students=1.515×32=48.48.

Let x denote the mean height of 18 girls.

Hence, sum of height of 18 girls is: 18 x.

Now,

18x+21.84=48.48

( since sum of height of girls and boys is equal to the sum of height of all the students)

so, 18x=48.48-21.84

18 x=26.64

Hence, x=1.48

Hence, Mean height of the girls is: 1.48

4 0
3 years ago
Which statment is true
Paraphin [41]
I think hamburger and French fries
6 0
3 years ago
WILL GIVE BRAINLIEST!!!!
Vesna [10]

(2^8 \times 5^{-5} \times 19^0)^{-2} \times (\dfrac{5^{-2}}{2^3})^4 \times 2^{28} =

= 2^{-16} \times 5^{10} \times 1 \times \dfrac{5^{-8}}{2^{12}} \times 2^{28}

= 2^{-16} \times 5^{10} \times 5^{-8} \times 2^{-12} \times 2^{28}

= 2^{-16} \times 2^{-12} \times 2^{28} \times 5^{10} \times 5^{-8}

= 2^{-16-12+28} \times 5^{10-8}

= 2^{0} \times 5^{2}

= 1 \times 25

= 25

7 0
3 years ago
Which one is correct ?
mina [271]

Answer:

Answer choice B

Step-by-step explanation:

The measures of angles on touching the opposite sides of the circles are always half the lengths of their respective arc. 126/2=63, or answer choice B. Hope this helps!

3 0
3 years ago
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HELP DUE IN 10 MINUTES WILL GIVE BRAINLEST!!
Pachacha [2.7K]

y-intercept: (0, 7)

x-intercept: (-\frac{7}{4},0)\\

5 0
2 years ago
Read 2 more answers
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