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lesantik [10]
3 years ago
12

Find the values ​​of x and y for the following matrix equations​

Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
3 0

Answer:

Step-by-step explanation:

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5/3-x+1/3

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The base and sides of a container is made of wood panels. The container does not have a lid. The base and sides are rectangular.
vfiekz [6]

Answer:

Minimum surface area =70.77 cm^2

Step-by-step explanation:

We are given that

Width of container=x cm

Length of container=2x cm

Volume of container=54 cm^3

We have to find the minimum surface areas that this container will have.

Volume of container=l\times b\times h

x\times 2x\times h=54

2x^2h=54

h=\frac{54}{2x^2}=\frac{27}{x^2}

Surface area of container=2(b+l)h+lb

Because the container does not have lid

Surface area of container=S=2(2x+x)\times \frac{27}{x^2}+2x\times x

S=\frac{162}{x}+2x^2

Differentiate w.r.t x

\frac{dS}{dx}=-\frac{162}{x^2}+4x

\frac{dx^n}{dx}=nx^{n-1}

Substitute \frac{dS}{dx}=0

-\frac{162}{x^2}+4x=0

4x=\frac{162}{x^2}

x^3=\frac{162}{4}=40.5

x^3=40.5

x=(40.5)^{\frac{1}{3}}

x=3.4

Again differentiate w.r.t x

\frac{d^2S}{dx^2}=\frac{324}{x^3}+4

Substitute x=3.4

\frac{d^2S}{dx^2}=\frac{324}{(3.4)^3}+4=12.24>0

Hence, function is minimum at x=3.4

Substitute x=3.4

Then, we get

Minimum surface area =\frac{162}{(3.4)}+2(3.4)^2=70.77 cm^2

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