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Arada [10]
3 years ago
6

What parcent of line segment AB is equal to 50% of line segmengCD

Mathematics
1 answer:
wel3 years ago
6 0
100%...................
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Hannah has 4 liters of cooking oil in a bottle. She used 1 1/2 liters of the oil. How much liters of oil are left in the bottle?
Scrat [10]

Hannah has 2\frac{1}{2} liters of oil left in the bottle.

Step-by-step explanation:

Given,

Quantity of oil in bottle = 4 liters

Quantity used by Hannah = 1\frac{1}{2} = \frac{3}{2}

We will subtract the quantity used from the total quantity.

Oil left = Total oil - Oil used

Oil\ left=4-\frac{3}{2}

Taking LCM

Oil\ left=\frac{8-3}{2}\\\\Oil\ left=\frac{5}{2}\\\\Oil\ left=2\frac{1}{2}

Hannah has 2\frac{1}{2} liters of oil left in the bottle.

Keywords: fraction, subtraction

Learn more about fractions at:

  • brainly.com/question/4163549
  • brainly.com/question/4168505

#LearnwithBrainly

7 0
3 years ago
Read 2 more answers
How is this one solved?
Vadim26 [7]

Answer:

  see below

Step-by-step explanation:

This is solved by simplifying each expression and identifying the column heading it matches.

1. (6 x^2/(x^2 - 7 x + 10)) / (2 x)/(x - 5))

= (6 x^2/(x^2 - 7 x + 10)) · (x -5)/(2 x) . . . . invert and multiply

= (6x^2)/(2x) · (x -5)/((x -2)(x -5)) . . . . . . . factor so common factors can cancel

= 3x/(x -2) . . . . matches column 1

__

2. (x - 4) (x + 2)/(x^2 + 5 x + 6) + (-3 x^2 + 24 x - 20)/((x + 3) (4 x - 5))

= (x -4)(x +2)/((x +3)(x +2)) + (-3x^2 +24x -20)/((x +3)(4x -5)) . . . factor

= (x -4)/(x +3) + (-3x^2 +24x -20)/((x +3)(4x -5)) . . . . cancel common factor

= ((x -4)(4x -5) +(-3x^2 +24x -20))/((x +3)(4x -5)) . . . . use common denominator

= (4x^2 -21x +20 -3x^2 +24x -20)/((x +3)(4x -5)) . . . expand product

= (x^2 +3x)/((x +3)(4x -5)) . . . . . . collect terms

= (x)(x +3)/((x +3)(4x -5)) . . . . . . factor numerator

= x/(4x -5) . . . . . . . . . . . . . . . . . . cancel common factor ... matches column 2

__

3. 3 x^2/(x + 3) · (2 x + 6)/(2 x^2 - 4 x)

= 3·2·x·(x +3)/((x +3)(2·x)(x -2)) = 3/(x -2) . . . . matches column 1

__

4. 3 x/(4 x - 5) - 4 x^2/(8 x^2 - 10 x)

= 3x/(4x -5) - 4x^2/(2x(4x -5)) = (3x -2x)/(4x -5) = x/(4x -5) ... matches col 2

__

5. 5 x^2/(x - 2) · (2 x + 6)/(8 x^2 - 4 x) . . . . no match (has a denominator factor of 2x-1 that doesn't cancel any numerator factors)

__

6. -x/(4 x - 5) - 4 x^2/(16 x^2 - 22 x)

In order to match one of the columns, the term on the right must reduce to 2x/(4x-5), which it does not, or must have a denominator factor of x-2, which it also does not. no match.

4 0
3 years ago
Please help with part A
Mrac [35]
You should convert it
3 0
3 years ago
Read 2 more answers
Find the value of x so that the function has the given value.<br> k(x)=7;k(x)=49
geniusboy [140]

Answer:

i don't what you want me to do here...

You gave me the same problem just two different numbers so maybe the answer is 7... idek tho bro

k times x = 7

k times x = 49

Step-by-step explanation:

6 0
3 years ago
HELP!! Can someone help me with this
cricket20 [7]

Answer:

1 no

2yes

3 no

4 no

5 Yes

6 Yes.

so it gives you a pattern right there a squared plus b squared equals c squared just fill in the numbers in that way

6 0
3 years ago
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