Answer: the first one.
Step-by-step explanation:
because distance on a number line will always be positive. :D
Answer:
So.. I believe the answer is 17
Step-by-step explanation:
In order to get your answer, you would first multiply 38*12 which is 456
Then you would get that number (456) and divide it by 7,752
So 7,752/456 is 17
Answer:
Standard error = 0.4
Step-by-step explanation:
Step 1
We find the Standard Deviation
The formula = √(x - mean)/n - 1
n = 15
Mean = 1.93 hours
= √(0- 1.93)² + (0-1.93)² +(0- 1.93)²+( 0- 1.93)²+ (1- 1.93)² + (1- 1.93)² +(1 - 1.93)² +(2 - 1.93)² + (2 - 1.93)² + (2 - 1.93)² + (2 - 1.93)² + ( 2 - 1.93)² +(4 - 1.93)² +(4 - 1.93)² + (5 - 1.93)²/15 - 1
= √(3.737777776 + 3.737777776 + 3.737777776 + 0.871111111 +0.871111111 + 0.871111111 + 0.004444444445+ 0.004444444445 + 0.004444444445 + 0.004444444445 + 0.004444444445 + 1.137777778 + 4.271111112 + 4.271111112 + 9.404444446)/15 - 1
= √2.352380952
= 1.533747356
Step 2
We find the standard error
The formula = Standard Deviation/√n
Standard deviation = 1.533747356
n = 15
= 1.533747356/√15
= 1.533747356 /3.87298334621
= 0.39601186447
Approximately = 0.4
Therefore, the standard error is 0.4
Answer:
Functions can be graphed
Each input in a function has one output
Function values can be shown on an input/output table
Step-by-step explanation:
Functions CAN have more than one variable, and CAN have more than 1 solution
the vertical component of the casting velocity will be reduce to zero at point h by the force of gravity.
If we use the kinematic equation
vf² = vi² +2as
and realize that the final vertical velocity is zero
and the initial vertical velocity is vsinθ
where θ is the angle of cast above the horizon
0 = vsin25 + 2(-9.8)h
h = 0.423v / 19.6
h = 0.02156v
so the missing potential heights and the associated answer velocities are
v = 19 m/s...h = 0.410 m
v = 8.3 m/s...h = 0.179 m
v = 6.9 m/s...h = 0.149 m
v = 8.4 m/s...h = 0.181 m
choose the one that fits the question
or use the method to find the correct velocity based on the actual height reference frame.
