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kifflom [539]
3 years ago
13

When developing an experimental design, which action could a scientist take

Physics
1 answer:
NNADVOKAT [17]3 years ago
6 0

Answer:

B.Include as many details as possible when writing the conclusion.

This helps improve the quality of their experiment..

_Askmeanything2♡

You might be interested in
When a bow is stretched it stores 10j and the arrows mass is 50g as it is projected show that the arrow has a speed of 20m/s
asambeis [7]

Answer:

20 m/s

Explanation:

The stored energy is transformed to kinetic energy and since kinetic energy is given by

0.5mv^{2}

where m is the mass of arrow in Kg and v is the velocity of the arrow in m/s. From the principle of energy, all the energy is transformed to KE.

KE= Energy stored in bow

Changing mass from 50 g to Kg we divide by 1000 hence m=50/1000=0.05 Kg

Substituting 0.05 Kg for m and 10 J for KE then we have

0.5\times 0.05\times v^{2}=10 J

Making v the subject of the formula then

v=\sqrt {\frac {10 J}{0.5\times 0.05 Kg}}=20\ m/s

Therefore, the velocity is equivalent to 20 m/s

6 0
3 years ago
If it takes 150N of force to move a box 10 meters. what is the work done on the box?
sergeinik [125]

Answer:

1500 Joules

Explanation:

Work = Force x Distance

When multiplying by 10 you simply shift all the digits to the

left and append a 0 to the end.

so 150 x 10 = 1500 Joules

3 0
3 years ago
Read 2 more answers
The electric field strength at a point in space a fixed (known) distance from a point charge source is 5000 N/C. How does the fi
Romashka-Z-Leto [24]

Answer:

See explanation

Explanation:

Electric field strength;

E = kq/d^2

k= coulombs constant

q= magnitude of charge

d = distance if separation

If

d is constant

q = 2q

Then;

E = 2 kq/d^2

Hence, the electric field strength will double.

7 0
3 years ago
Which of these is an example of energy transfer by radiation?
andrezito [222]

Answer:

Hands rubbed together to become warm

6 0
3 years ago
Read 2 more answers
Calcula el peso aparente de una bola de aluminio de 50 cm3, cuando se encuentra totalmente sumergida en alcohol. Datos: la densi
artcher [175]

Answer:

W_apparent = 93.1 kg

Explanation:

The apparent weight of a body is the weight due to the gravitational attraction minus the thrust due to the fluid where it will be found.

            W_apparent = W - B

The push is given by the expression of Archimeas

            B = ρ_fluide g V

            ρ_al = m / V

            m = ρ_al V

we substitute

            W_apparent = ρ_al V g - ρ_fluide g V

            W_apparent = g V (ρ_al - ρ_fluide)

       

we calculate

           W_apparent = 980 50 (2.7 - 0.8)

           W_apparent = 93100 g

            W_apparent = 93.1 kg

7 0
3 years ago
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