When it reaches it's peak, the energy is converted into potential as it slows down, then back to kinetic as it goes back to the lowest point.
Answer:
Explanation:
Given that,
AC frequency of 2.3KHz
f=2.3×10³Hz
Vrms produce is
Vrms=1.5V
Current rms
Irms= 31mA
The capacitor is reconnected to a generator of frequency
f=4.8KHz =4800Hz
The current rms becomes
Irms= 85mA
Vrms=?
Solution
First genrator
The capacitive reactance is given as
Xc=Vrms/Irms
Xc=1.5/31×10^-3
Xc=48.39 ohms
Now, to know the capacitance of the capacitor
Xc=1/2πfC
Then,
C=1/2πfXc
So,
C=1/2×π×2300×48.39
C=1.43×10^-6C
C=1.43μF
Note: the capacitance of the capacitor did not change,
Now for generator two.
The reactance are given as
Xc=1/2πfC
Xc=1/2×π×4800×1.43×10^-6
Xc=23.19ohms
Then,
Vrms2=Irms2 ×Xc
Vrms2=85×10^-3×23.19ohms
Vrms2=1.97V
Vrms2=1.97Volts
Answer: 0.0267m/s
Explanation: Wave speed in m/s
Speed = Distance/Time
Substitute the given values into the formula
Speed = 0.1/3.75
Speed = 0.0267m/s
Answer:
1-d
2- a
3-e
4-b
5-c
This is the correct sequence
Explanation:
Missing Details. Most models can't incorporate all the details of complex natural phenomena.
Most Are Approximations. Most models include some approximations as a convenient way to describe something
