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Yuliya22 [10]
3 years ago
10

What is the median of the data set?

Mathematics
2 answers:
lana [24]3 years ago
6 0

Answer:

D. 22

22 is in the middle

There are three numbers on both sides of 22 so it makes it even and 22 ends up being in the middle.

Hope this helps

Tcecarenko [31]3 years ago
4 0
The answer is 22 it’s in the middle median is middle
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4 years ago
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Find the x- and y-intercepts for the following equation:<br> y=-3x + 27
emmasim [6.3K]
Y- intercept: 27
x-intercept: 9

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State the null and alternative hypotheses to test if the population represented by Sample 1 has a mean that is 2.0 units higher
avanturin [10]

Answer:

Null Hypothesis, H_0 : \mu_A-\mu_B = 2.0 units  or  \mu_D = 2.0 units

Alternate Hypothesis, H_A : \mu_A-\mu_B\neq 2.0 units  or  \mu_D\neq 2.0 units

Step-by-step explanation:

We are given the following data below and we have test if the population represented by Sample 1 has a mean that is 2.0 units higher than the population represented by Sample 2;

Pair : 1 2 3 4 5 6 7

Sample1 : 5 6 10 3 6 7 8

Sample2 : 4 4 3 5 5 5 3

Let \mu_A = population mean represented by Sample 1

\mu_B = population mean represented by Sample 2

\mu_D = population mean matched-pair differences for Sample 1 - Sample 2

So, Null Hypothesis, H_0 : \mu_A-\mu_B = 2.0 units  or  \mu_D = 2.0 units

Alternate Hypothesis, H_A : \mu_A-\mu_B\neq 2.0 units  or  \mu_D\neq 2.0 units

Here null hypothesis states that the population represented by Sample 1 has a mean that is 2.0 units higher than the population represented by Sample 2.

On the other hand, alternate hypothesis states that the population represented by Sample 1 has a mean that is not 2.0 units higher than the population represented by Sample 2.

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4 years ago
What is the range of the one shown on the graph above​
sp2606 [1]

Answer:

idk

Step-by-step explanation:

5 0
3 years ago
How do you solve the inequality 6y+3&gt; -18x
Alex17521 [72]
6y + 3 \ \textgreater \  - 18 x

Subtract 3 from both sides:

6 y + 3 - 3 \ \textgreater \  - 18 x - 3

6y \ \textgreater \  - 18 x - 3

Dividade both sides by 6 :

\frac{6y}{6} \ \textgreater \   \frac{-18x-3}{6}

y \ \textgreater \  \frac{-18x-3}{6}

hope this helps!


6 0
3 years ago
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