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Ray Of Light [21]

3 years ago

12

Cookies are on sale! Today each cookie costs \$0.75$0.75dollar sign, 0, point, 75 less than the normal price. Right now if you b

uy 777 of them it will only cost you \$2.80$2.80dollar sign, 2, point, 80!

1 answer:

Elan Coil [88]3 years ago

7 0

I'm sorry, but what are you asking?

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Does anyone know how to do this (#2) PLZZZZ HELPPPPPPPP

timurjin [86]

Answer:

a.- slope= 36

Interpretation : The cable car travels 36 meter per minute

b.- y = 36x + 100

c.- 640 meters

Step-by-step explanation:

a.-

Find slope using the slope formula : $\frac{y2-y1}{x2-x1}$

Plug in the two given points: $\frac{1000-100}{25-0}$

Subtract the numbers : $\frac{900}{25}$

Reduce the fraction : 36

b.-

Using the given y-interspet (100) and the slope create an equation: y = 36x + 100

c.-

Using the equation you created plug in 15 for x to find the

distance: y = 36 (15) + 100

Multiply the numbers : y = 540 + 100

Add the numbers : y = 640

8 0

3 years ago

Patricia knows she can request a free copy of her credit report each year, but now that she's got the document, she's not sure w

kap26 [50]

Answer:

Macaron are the best

Step-by-step explanation:

3 0

3 years ago

Pls solve the simultaneous equation in the attachment.

siniylev [52]

Answer:

Part a) The solution is the ordered pair (6,10)

Part b) The solutions are the ordered pairs (7,3) and (15,1.4)

Step-by-step explanation:

Part a) we have

$\frac{x}{2}-\frac{y}{5}=1$ ----> equation A

$y-\frac{x}{3}=8$ ----> equation B

Multiply equation A by 10 both sides to remove the fractions

$5x-2y=10$ ----> equation C

isolate the variable y in equation B

$y=\frac{x}{3}+8$ ----> equation D

we have the system of equations

$5x-2y=10$ ----> equation C

$y=\frac{x}{3}+8$ ----> equation D

Solve the system by substitution

substitute equation D in equation C

$5x-2(\frac{x}{3}+8)=10$

solve for x

$5x-\frac{2x}{3}-16=10$

Multiply by 3 both sides

$15x-2x-48=30$

$15x-2x=48+30$

Combine like terms

$13x=78$

$x=6$

<em>Find the value of y</em>

$y=\frac{x}{3}+8$

$y=\frac{6}{3}+8$

$y=10$

The solution is the ordered pair (6,10)

Part b) we have

$xy=21$ ---> equation A

$x+5y=22$ ----> equation B

isolate the variable x in the equation B

$x=22-5y$ ----> equation C

substitute equation C in equation A

$(22-5y)y=21$

solve for y

$22y-5y^2=21$

$5y^2-22y+21=0$

Solve the quadratic equation by graphing

The solutions are y=1.4, y=3

see the attached figure

<em>Find the values of x</em>

For y=1.4

$x=22-5(1.4)=15$

For y=3

$x=22-5(3)=7$

therefore

The solutions are the ordered pairs (7,3) and (15,1.4)

3 0

4 years ago

Solving quadratic equations using square roots

masya89 [10]

Answer:

i hope you understand this

8 0

3 years ago

If I get played 9$ an hour and I work 8:15 a day how much do I get for 5 days

Thepotemich [5.8K]

First of all, 15 minutes is 1/4 of an hour. So 8:15 is 8.25 hours.

(8.25 hours/day) x ( 9 $/hour) x (5 days) = $371.25

7 0

3 years ago

Read 2 more answers