Answer:
110 in. = 9 1/6 ft, or 9 ft 2 in
Step-by-step explanation:
Please try to do a better job of formatting your next question. Thanks.
110 in 1 ft
-------- * --------- = 9 1/6 ft or 9 ft 2 in
1 12 in
Answer:
Solution given:
Since the given triangle is isosceles and right angled triangle
perpendicular [p]=base[b]=x
hypotenuse [h]=6
we have
by using Pythagoras law
p²+b²=h²
x²+x²=6²
2x²=36
x²=36/2
x²=18
x=
<u>x</u>=
Answer:
13
Step-by-step explanation:
The average rate of change of f(x) in the closed interval [ a, b ] is

Here [ a, b ] = [2, 6 ]
f(b) = f(6) = 6² + 5(6) - 8 = 36 + 30 - 8 = 58
f(a) = f(2) = 2² + 5(2) - 8 = 4 + 10 - 8 = 6
Hence
average rate of change =
=
= 13
Answer:
The minimum sample size needed for use of the normal approximation is 50.
Step-by-step explanation:
Suitability of the normal distribution:
In a binomial distribution with parameters n and p, the normal approximation is suitable is:
np >= 5
n(1-p) >= 5
In this question, we have that:
p = 0.9
Since p > 0.5, it means that np > n(1-p). So we have that:





The minimum sample size needed for use of the normal approximation is 50.
Answer:
D
Step-by-step explanation:
It just is