In this exercise, you're required to write an expression for the total cost of the daycare for Lucy's dog this week. Thus, we would assign a variable to the cost for full-day and half-day day care as follows:

Let the cost for full-day be F.

Let the cost for half-day be H.

Let total cost be T.

Thus, the total cost of the daycare is given by:

T = 3F + 2H

Evaluating the expression, we have:

T = 3(28) + 2(15)

T = 84 + 30

T = $114.

Read more on expressions here: brainly.com/question/12189823

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7 0

2 years ago

A class consists of 23 women and 83 mean. If a student is random selected, what is the probability that the student is a woman?

slavikrds [6]

Answer:

$P(Woman) = \frac{23}{106}$

Step-by-step explanation:

Given

$Women = 23$

$Men = 83$

Required

$P(Woman)$

This is calculated as the number of women divided by the population of the class

i.e.

$P(Woman) = \frac{Women}{Women + Men}$

So, we have:

$P(Woman) = \frac{23}{23+83}$

$P(Woman) = \frac{23}{106}$

7 0

2 years ago