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Anna11 [10]
3 years ago
6

What is m% of n? Please help!

Mathematics
1 answer:
melisa1 [442]3 years ago
3 0

Answer:

nm/100

Step-by-step explanation:

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Match the one-to-one functions with their inverse functions.
Nady [450]
The inverse of a function is obtained by making x the subject of the formular of the function.

Given the function
f(x)= \frac{x}{8} -7
the inverse of the function is obtained as follows:
y= \frac{x}{8} -7 \\  \\ y+7=\frac{x}{8} \\  \\ x=8(y+7) \\  \\ \bold{f^{-1}(x)=8(x+7)}

Given the function
[tex[f(x)=x+7[/tex]
the inverse of the function is obtained as follows:
y=x+7 \\  \\ x=y-7 \\  \\ \bold{f^{-1}(x)=x-7}

Given the function
f(x)=1- \frac{x}{3}
the inverse of the function is obtained as follows:
y=1- \frac{x}{3} \\  \\  -\frac{x}{3} =y-1 \\  \\ x=-3(y-1) \\  \\ \bold{f^{-1}(x)=-3(x-1)}

Given the function
f(x)=20-0.25x
the inverse of the function is obtained as follows:
y=20-0.25x=20- \frac{1}{4} x \\  \\ \frac{1}{4} x=20-y \\  \\ x=4(20-y) \\  \\ \bold{f^{-1}(x)=4(20-x)}
5 0
3 years ago
What is the base of the trapezoid with an area of 150 a height of 10 and a base of 14?
slavikrds [6]
The formula for the area of a trapezoid is:

A= (a+b)/2*h

A=150
h=10
b=14
a=?

So we need to solve for a. Let's plug in the values that we do know...

A= (a+b)/2*h
150=(a+14)/2*10
150=(a/2+14/2)*10
150=(a/2+7)*10
Divide both sides by 10
15=a/2+7
subtract 7 from both sides
8=a/2
multiply both sides by 2
16=a

The other base is 16
3 0
4 years ago
Read 2 more answers
Solve for m. m + 95 /<br> 4 = 5
ExtremeBDS [4]

Answer:

m = -75/4

Step-by-step explanation:

1. Subtract 95/4 from both sides

m + 95/4 = 5

x + 95/4 - 95/4 = 5 - 95/4

2. Simplify, which will get you -75/4

7 0
3 years ago
Please help with math
pshichka [43]
I did some research, and I think it's the first one. PLEASE CORRECT ME IF I'M WRONG!!
Here's why, because the first segment extends from 0 to 1. So, x has to be 0 or larger, but less than 1 or 1.
5 0
3 years ago
What is the value of a?
Artemon [7]
The value has to be 14
4 0
4 years ago
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