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3 years ago

If you help me, you will get this cookie

Mathematics

2 answers:

goblinko [34]3 years ago

6 0

Answer:

b. 7y-15

Step-by-step explanation:

First, write out the expression

1. $10y-3(y+5)$

To simplify the expression distribute the -3 to the terms within the paratheses.

2. $10y-3y-15$

Then, combine like terms to simplify further. Since 10y and -3y are like terms they can be subtracted

3. $7y-15$

This means that B is the correct answer.

GuDViN [60]3 years ago

5 0

Answer:

B. 7y - 15

Step-by-step explanation:

Simplifying

10y + -3(y + 5) = 0

Reorder the terms:

10y + -3(5 + y) = 0

10y + (5 * -3 + y * -3) = 0

10y + (-15 + -3y) = 0

Reorder the terms:

-15 + 10y + -3y = 0

Combine like terms: 10y + -3y = 7y

-15 + 7y = 0

Solving

-15 + 7y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '15' to each side of the equation.

-15 + 15 + 7y = 0 + 15

Combine like terms: -15 + 15 = 0

0 + 7y = 0 + 15

7y = 0 + 15

Combine like terms: 0 + 15 = 15

7y = 15

Divide each side by '7'.

y = 2.142857143

Simplifying

y = 2.142857143

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A 2005 survey found that 7% of teenagers (ages 13 to 17) suffer from an extreme fear of spiders (arachnophobia). At a summer cam

bagirrra123 [75]

Answer:

Probability that at least one of them suffers from arachnophobia is 0.5160.

Step-by-step explanation:

We are given that a 2005 survey found that 7% of teenagers (ages 13 to 17) suffer from an extreme fear of spiders (arachnophobia).

Also, At a summer camp there are 10 teenagers sleeping in each tent.

Firstly, the binomial probability is given by;

$P(X=r) =\binom{n}{r}p^{r}(1-p)^{n-r} for x = 0,1,2,3,....$

where, n = number of trials(teenagers) taken = 10

r = number of successes = at least one

p = probability of success and success in our question is % of

the teenagers suffering from arachnophobia, i.e. 7%.

Let X = Number of teenagers suffering from arachnophobia

So, X ~ $Binom(n= 10,p=0.07)$

So, probability that at least one of them suffers from arachnophobia

= P(X >= 1) = 1 - probability that none of them suffers from arachnophobia

= 1 - P(X = 0) = 1 - $\binom{10}{0}0.07^{0}(1-0.07)^{10-0}$

= 1 - (1 * 1 * $0.93^{10}$ ) = 1 - 0.484 = 0.5160 .

Therefore, Probability that at least one of them suffers from arachnophobia is 0.5160 .

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3 years ago

Which statements are true about the solution of 15 > 22+ x? Select three options.

Evgesh-ka [11]

Answer:

$x \leqslant - 7 \\ the \: graph \: has \: a \: closed \: circle \\ - 7 \: is \: a \: part \: of \: the \: solution$

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3 years ago

Answer this. And youll get moneyyy

musickatia [10]

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3 years ago

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Determine the equation of each of the following parabolas

Pani-rosa [81]

Step-by-step explanation:

For graphs where the zeros (x-intercepts) are known, use the factored form of a parabola:

y = a (x − b) (x − c)

where (b, 0) and (c, 0) are the zeros. Plug in a third point to find the value of a.

For graphs where the vertex is known, use the vertex form of a parabola:

y = a (x − h)² + k

where (h, k) is the vertex. Plug in a second point to find the value of a.

I'll do the first three problems as examples.

a) The vertex is (0, 5), and one of the zeros is (4, 0). Since the vertex is halfway between the zeros, we also know the other zero is (-4, 0). So we can use either form.

Using factored form:

y = a (x − 4) (x − (-4))

y = a (x − 4) (x + 4)

Plug in the vertex to find the value of a:

5 = a (0 − 4) (0 + 4)

5 = -16a

a = -5/16

Therefore, the equation is:

y = -5/16 (x − 4) (x + 4)

b) The vertex is (0, 0). It is also the only root. So again, we can use either form.

Using vertex form:

y = a (x − 0)² + 0

y = ax²

Plugging in the second point:

9 = a (-3)²

9 = 9a

a = 1

Therefore, the equation is:

y = x²

c) This time, we don't know the coordinates of the vertex, but we do know the roots are (-7, 0) and (0, 0). Using factored form:

y = a (x − 0) (x − (-7))

y = a x (x + 7)

Plugging in the third point:

4 = a (4) (4 + 7)

4 = 44a

a = 1/11

Therefore, the equation is:

y = 1/11 x (x + 7)

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3 years ago

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Sladkaya [172]

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