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3 years ago

What is the inverse function of y=5x + 1

Mathematics

1 answer:

Semenov [28]3 years ago

5 0

Answer:

5x - 1

Step-by-step explanation:

i don't know hw to explain it but that's the answer

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HELP PLS:

Ne4ueva [31]

Answer:

Bruce's function:

$\displaystyle y=\frac{1}{4}x$

Felicia's function:

$\displaystyle y=\frac{1}{9}x$

<em>Bruce's tiles cover more area</em>

Step-by-step explanation:

<u>Functions </u>

We need to compare the area covered by tile of both Bruce and Felicia. We are required to find the function y, the area covered by the number of tiles he used, x.

We know the tiles used by Bruce cover 1/4 of a square foot, this is written as:

$\displaystyle y=\frac{1}{4}x$

To find the function for Felicia, we must use the data provided in the table

For example,

For x=9 tiles, y=1 sq ft

For x=18 tiles, y=2 sq ft

If we set

$\displaystyle y=kx$

We can find the value of k

$\displaystyle 1=9k$

$\displaystyle k=\frac{1}{9}$

Thus

$\displaystyle y=\frac{1}{9}x$

Testing the constructed function with x=18 and x=27

$\displaystyle y=\frac{1}{9}18=2$

$\displaystyle y=\frac{1}{9}27=3$

The function is complete and accurate.

Comparing both functions we see that Bruce's tiles cover more area because

$\displaystyle \frac{1}{4}>\frac{1}{9}$

7 0

4 years ago

Read 2 more answers

First-order linear differential equations

kkurt [141]

Answer:

$(1)\ logy\ =\ -sint\ +\ c$

$(2)\ log(y+\dfrac{1}{2})\ =\ t^2\ +\ c$

Step-by-step explanation:

1. Given differential equation is

$\dfrac{dy}{dt}+ycost = 0$

$=>\ \dfrac{dy}{dt}\ =\ -ycost$

$=>\ \dfrac{dy}{y}\ =\ -cost dt$

On integrating both sides, we will have

$\int{\dfrac{dy}{y}}\ =\ \int{-cost\ dt}$

$=>\ logy\ =\ -sint\ +\ c$

Hence, the solution of given differential equation can be given by

$logy\ =\ -sint\ +\ c.$

2. Given differential equation,

$\dfrac{dy}{dt}\ -\ 2ty\ =\ t$

$=>\ \dfrac{dy}{dt}\ =\ t\ +\ 2ty$

$=>\ \dfrac{dy}{dt}\ =\ 2t(y+\dfrac{1}{2})$

$=>\ \dfrac{dy}{(y+\dfrac{1}{2})}\ =\ 2t dt$

On integrating both sides, we will have

$\int{\dfrac{dy}{(y+\dfrac{1}{2})}}\ =\ \int{2t dt}$

$=>\ log(y+\dfrac{1}{2})\ =\ 2.\dfrac{t^2}{2}\ + c$

$=>\ log(y+\dfrac{1}{2})\ =\ t^2\ +\ c$

Hence, the solution of given differential equation is

$log(y+\dfrac{1}{2})\ =\ t^2\ +\ c$

8 0

4 years ago

1. What is the expanded form of the expression 3.6(t + 5)?

Fed [463]

Answer:

Step-by-step explanation:

1) The expanded form of 3.6(t + 5) is 3.6t + 18.

7 0

3 years ago

Read 2 more answers

The coordinates of the vertices of ∆PQR are P(-2,5), Q(-1,1), and R(7,3). Determine whether ∆PQR is a right triangle. Show your

Mashutka [201]

Given

∆PQR points are P(-2,5), Q(-1,1), and R(7,3)

Determine whether ∆PQR is a right triangle

To proof

As given ∆PQR points are P(-2,5), Q(-1,1), and R(7,3)

First find out the sides of triangle

FORMULA

Distance formula between two points

$D^{2}= (x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}$

Distance between two points P(-2,5) and Q(-1,1)

$PR = \sqrt{(-1+2)^{2}+(1-5)^{2} }$

$PR = \sqrt{17}$

Distance between two points Q(-1,1)and R(7,3)

$QR = \sqrt{(7+1)^{2} +(3-1)^{2} }$

$QR =\sqrt{68}$

Distance between two points R(7,3) and P(-2,5)

$RP =\sqrt{(-2-7)^{2} + (5-3)^{2} }$

$RP=\sqrt{85}$

now show that ∆PQR is a right triangle

$RP^{2} = PQ^{2} +QR^{2}$

Putting the value given above

$(\sqrt{85}) ^{2} = \sqrt{17} ^{2} +\sqrt{68} ^{2}$

85 = 17 +68

85 =85

In the right triangle

HYPOTENUSE² = BASE² + PERPENDICULAR²

This is prove above

Hence ∆PQR is a right triangle

Hence proved

7 0

4 years ago

Jenna is going at a constant rate of 4 miles per hour. It takes her 2 hours to get to her destination. How long would it take to

fgiga [73]

Answer:

6hrs

Step-by-step explanation:

because 4-2hrs 4x3=12 so it's 8

and it's fall guys

7 0

3 years ago

Read 2 more answers