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vivado [14]
4 years ago
6

Plz help its urgent

Chemistry
1 answer:
goldfiish [28.3K]4 years ago
8 0

Answer:

The answer to this is D.

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The molar madd of Ca(OH)2
Nonamiya [84]
What you have to do is find a periodic table and add the mass of each atom that the compound is made of.

Ca= 40.1
O= 16.0
H= 1.01

keep in mind that you have to also account for how many atoms of each there are in the molecule. for example, in Ca(OH)2, there are one Ca, two O and two H

so the molar mass of Ca(OH)2= 40.1 + (2 x 16.0) + (2 x 1.01)= 74.12 g/mol
8 0
3 years ago
A certain indicator has a color chart that shows that when the indicator is yellow, the solution is acidic. What is true about a
bija089 [108]
It’s acidic?
It tastes sour
It has at least one hydrogen molecule
4 0
4 years ago
The compound 1-butene is modeled here. What would need to happen for molecules of this compound to transform into polybutene? A.
kompoz [17]
In order to form polymers, we need to chain molecules together. This involves making bonds between them.

Shifting H’s around doesn’t accomplish anything.

Forming more double bonds will have the opposite result, as it would make the molecules more stable and less likely to react with each other.

Adding oxygen to the molecule no longer makes it polybutene. That would likely result in the formation of some sort of ether, as hey would react to form a C-O-C Bond.

The only answer left is A. In order to form polyalkenes, we have to break a double bond so that it’s available to form more covalent bonds.

Hope this helps
4 0
4 years ago
What type of bond will form between potassium and iodine
ella [17]

Answer:

ionic bond

Explanation:

5 0
3 years ago
Electric power is measured in watts (1 W = 1 J/s). About 95% of the power output of an incandescent bulb is converted to heat an
nlexa [21]

Answer:

9.430 * 10¹⁷ protons per second whill shine on the book from a 62 W bulb

Explanation:

To answer this question, first let's calculate the energy of a single photon with a wavelength (λ) of 504 nm:

E = hc/λ

Where h is Planck's constant (6.626*10⁻³⁴ J·s) and c is the speed of light (3*10⁸ m/s).

E = 6.626*10⁻³⁴ J·s * 3*10⁸ m/s ÷ (504*10⁻⁹m) = 3.944 * 10⁻¹⁹ J.

So now we can make the equivalency for this problem, that

<u>1 proton =  3.944 * 10⁻¹⁹ J</u>

Now we convert watts from J/s to proton/s:

1 \frac{J}{s}*\frac{1proton}{3.944*10^{-19}J}=2.535*10^{18} \frac{proton}{s} = 1 W

Solving the problem, a 62 W bulb converts 5% of its output into light, so:

  • 62 * 5/100 = 3.1 W

3.1 watts are equal to [ 2.535*10¹⁸ proton/s * 3.1 ] = 7.858 * 10¹⁸ proton/s

Of those protons per second, 12% will shine on the chemistry textbook, thus:

7.858 * 10¹⁸ proton/s * 12/100 = 9.430 * 10¹⁷ protons/s

8 0
3 years ago
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