√272 is a real number, and the simplified expression of √272 is 4√17
<h3>How to simplify the expression?</h3>
The expression is given as:
√272
Expand
√272 = √16 * 17
Take the square root of 16
√272 = 4√17
Hence, the simplified expression of √272 is 4√17
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Answer:
<h3>
a. 3x+15</h3><h3>
b. 4x-16</h3><h3>
c. 10x+2</h3><h3>
D. 7x-63y</h3>
solution,




Hope this helps..
Good luck on your assignment..
Answer:
No real roots
Step-by-step explanation:
Given
7x² + 5x + 1 = 0 ← in standard form
with a = 7, b = 5, c = 1
To determine the nature of the roots use the discriminant
Δ = b² - 4ac
• If b² - 4ac > 0 then roots are real and distinct
• If b² - 4ac = 0 then roots are real and equal
• If b² - 4ac < 0 then the roots are not real
Here
b² - 4ac = 5² - (4 × 7 × 1) = 25 - 28 = - 3
Thus the 2 roots are not real
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