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ladessa [460]
3 years ago
11

Solve 4/r = 5/20 will mark brainliest ​

Mathematics
2 answers:
vazorg [7]3 years ago
7 0
R=16
how to solve:
cross multiply:))
Svetllana [295]3 years ago
3 0

Answer:

= 16

Step-by-step explanation:

Simplify  \frac{5}{20}

​20

​

​5

​​   to  \frac{1}{4}

​4

​

​1

​​ .

\frac{4}{r}=\frac{1}{4}

​r

​

​4

​​ =

​4

​

​1

​​

2 Multiply both sides by rr.

4=\frac{1}{4}r4=

​4

​

​1

​​ r

3 Simplify  \frac{1}{4}r

​4

​

​1

​​ r  to  \frac{r}{4}

​4

​

​r

​​ .

4=\frac{r}{4}4=

​4

​

​r

​​

4 Multiply both sides by 44.

4\times 4=r4×4=r

5 Simplify  4\times 44×4  to  1616.

16=r16=r

6 Switch sides.

r=16r=16

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3 years ago
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"This summer, the water level of Lake Conroe changed by a rate of -1.5 feet per month. The water level at the beginning of May w
Verdich [7]

Answer:

181 feets

Step-by-step explanation:

Given that:

Rate of change in water level = - 1.5 feets per month

Water level at beginning of May = 187 feets above sea level

Water level at the end of 4 months =?

Total change after four months = rate of change per month * number of months

= - 1.5 * 4 = - 6 feets

Hence water level after 4 months :

187 feets + (-6 feets)

187 feets - 6 feets

= 181 feets

8 0
3 years ago
Help me plz !!!!!! i need help be honest
klemol [59]
THE ANSER is commutative property of addition
4 0
4 years ago
Question 8 Find the unit vector in the direction of (2,-3). Write your answer in component form. Do not approximate any numbers
slamgirl [31]

Answer:

The unit vector in component form is \hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}}  \right) or \hat{u} = \frac{2}{\sqrt{13}}\,i-\frac{3}{13}\,j.

Step-by-step explanation:

Let be \vec u = (2,-3), its unit vector is determined by following expression:

\hat {u} = \frac{\vec u}{\|\vec u \|}

Where \|\vec u \| is the norm of \vec u, which is found by Pythagorean Theorem:

\|\vec u\|=\sqrt{2^{2}+(-3)^{2}}

\|\vec u\| = \sqrt{13}

Then, the unit vector is:

\hat{u} = \frac{1}{\sqrt{13}} \cdot (2,-3)

\hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}}  \right)

The unit vector in component form is \hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}}  \right) or \hat{u} = \frac{2}{\sqrt{13}}\,i-\frac{3}{13}\,j.

6 0
3 years ago
100 Points!!!
Mars2501 [29]

Let's see

#a

Take 28

  • (28)²
  • (30-2)²
  • 30²-2(30)(2)+2²
  • 900-120+4
  • 780+4
  • 784

#2

Take 9,10

  • 9³+10³
  • (9+10)(9²-9×10+10²)
  • (19)(81-90+100)
  • 19(181-90)
  • 19(91)
  • 1729
7 0
2 years ago
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