Consider function f.
1 answer:
Answer:
- x = 2, x = -1, x = -3
- As x approaches negative infinity, f(x) approaches negative infinity
Step-by-step explanation:
<u>Given function</u>
- f(x)= x^3 + 2x^2 - 5x - 6
<u>Finding zero's</u>
- x^3 + 2x^2 - 5x - 6 = 0
- x^3 - 2x^2 + 4x^2 - 8x +3x - 6 =
- (x - 2)(x^2 + 4x + 3) =
- (x - 2)(x^2 + x + 3x + 3) =
- (x - 2)(x(x + 1) + 3(x + 3)) =
- (x - 2)(x + 1)(x + 3)
<u>Zero's are</u>
- x = 2, x = -1, x = -3
<em>See the graph attached</em>
<u>Correct end behavior as per graph:</u>
- As x approaches negative infinity, f(x) approaches negative infinity
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<h2>The required 'option a) - 9 , 
, 4' is correct.</h2>
Step-by-step explanation:
We have,
f(x) = (x + 9)(x − 4)(6x + 1)
To find, all zeroes of the given equation = ?
∴ f(x) = (x + 9)(x − 4)(6x + 1)
⇒ (x + 9)(x − 4)(6x + 1) = 0
⇒ x + 9 = 0 or, x − 4 = 0 or, 6x + 1 = 0
⇒ x + 9 = 0 ⇒ x = - 9
⇒ x − 4 = 0 ⇒ x = 4
⇒ 6x + 1 = 0
⇒ 6x = - 1
⇒ x =
∴ x = - 9 , , 4
Thus, the required 'option a) - 9 , , 4' is correct.