Answer:
Step-by-step explanation:
We are given that
Height of man=5 foot
Height of street light=20ft
We have to find the rate of change of the length of his shadow when he is 25 ft form the street light.
ABE and CDE are similar triangle because all right triangles are similar.
Hence, the rate of change of the length of his shadow when he is 25 ft from the street light=
Answer:
(5.4582 ; 6.8618)
Step-by-step explanation:
Given the data:
6 10 2 6 3 3 3 6 6 6 6 5 8 9 10 10 7 9 3 6 5 10 9 9 10 3 8 6 6 3 3 6 6 5 4 10 9 3 5 7 10 6 3 8 6 8 3 3 5 5
Sample mean, xbar = Σx / n
n = sample size = 50
ΣX = 308
xbar = 308 / 50 = 6.16
Using a Calculator :
The sample standard deviation, s = 2.469
Confidence interval = xbar ± margin of error
Margin of Error = Tcritical * s/sqrt(n)
Tcritical at 95% ; df = 50 - 1 = 49
Tcritical = 2.010
Hence,
Margin of Error= 2.010 * (2.469/sqrt(50)) = 0.7018
Lower boundary : (6.16 - 0.7018) = 5.4582
Upper boundary : (6.16 + 0.7018) = 6.8618
(5.4582 ; 6.8618)
Answer:
32
Step-by-step explanation:
First you're going to change 20% to a decimal which would be 0.20
Next, multiply .20 by 40
You should get 8
Subtract 8 from 40
You're answer is 32
Reflection of point (x ,y) about x axis is given by (x,-y) and about y axis is given by (-x,y) .treat the line as plane mirror about which you have to find out point reflection .thus Q is (5 ,-6) and R is(-5,6)..
Answer:
Area = Length × width
16 = (3x +2 ) × ( x)
16 = 3x² +2x
3x² +2x -16=0
( 3x+8 ) ( x -2 ) =0
3x +8=0 —> 3x = – 8 —> x = – 8/3 —> x = – 2.6
x-2=0 —> x = 2
I hope I helped you^_^
