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Mice21 [21]
3 years ago
10

What are the different methods in finding the LCM​

Mathematics
1 answer:
Nezavi [6.7K]3 years ago
8 0

Answer:

4 methods are there

Step-by-step explanation:

  1. Find the prime factorization of each number.
  2. Write each number as a product of primes, matching primes vertically when possible.
  3. Bring down the primes in each column.
  4. Multiply the factors to get the LCM.

please mark me as brainlist

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If 4x - 8 = 4 , find the value of x​
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Answer:

x=3

Step-by-step explanation:

4x-8=4

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4x/4=12/4

x=3

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3 years ago
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Write an equation for a rational function with: Vertical asymptotes at x = -4 and x = 2 x-intercepts at x = -2 and x = -3 Horizo
Dominik [7]

Answer:

Correct answer:  y = ( 3x² + 15x + 18) / (x² + 2x - 8)

Step-by-step explanation:

The function has vertical asymptotes at points where it is not defined.

In our case it is at  x₁ = -4 and x₂ = 2

This means that the function in the denominator has a quadratic function whose roots are (x + 4) · (x - 2) = x² + 2x - 8

The function intercepts x axis at x₀₁ = -2 and x₀₂ = -3

This means that the function in the numerator has a quadratic function whose roots are (x + 2) · (x + 3) = x² + 5x + 6

The function currently looks like this:

y = (x² + 5x + 6) / (x² + 2x - 8)

Since the function has a horizontal asymptote y = 3, this means when x strive to + - infinite or x -> + - ∞  then it is

lim x -> + - ∞ (x² + 5x + 6) / (x² + 2x - 8) = 3

This means that the function in the numerator must has term 3x² which we will get when we multiply the currently function y = (x² + 5x + 6) / (x² + 2x - 8)  by the number 3 and get :

y = 3 · (x² + 5x + 6) / (x² + 2x - 8) = (3x² + 15x + 18) / (x² + 2x - 8)

y = ( 3x² + 15x + 18) / (x² + 2x - 8)

God is with you!!!

4 0
3 years ago
Let U = {q, r, s, t, u, v, w, x, y, z}
Sliva [168]

The Set A’∪ B =  { r, t, v, x, z, q, s, y, z }

We have the following sets -

U = {q, r, s, t, u, v, w, x, y, z}

A = {q, s, u, w, y}

B = {q, s, y, z}

C = {v, w, x, y, z}

We have to determine the set represented by -  A' ∪ B.

<h3>What is a Set?</h3>

A set is a collection of elements or numbers or objects, represented within the curly brackets { }. For example: {1,2,3,4} is a set of numbers.

According to question, we have -

U = {q, r, s, t, u, v, w, x, y, z}    (Universal Set)

A = {q, s, u, w, y}

B = {q, s, y, z}

C = {v, w, x, y, z}

Consider Set A = {q, s, u, w, y}

A' = U - A = {q, r, s, t, u, v, w, x, y, z} - {q, s, u, w, y} = { r, t, v, x, z }

and Set B = {q, s, y, z}

Now -

A' ∪ B = { r, t, v, x, z }  ∪  {q, s, y, z} = { r, t, v, x, z, q, s, y, z }

Hence, the Set A’∪ B =  { r, t, v, x, z, q, s, y, z }

To solve more questions on Set theory, visit the link below -

brainly.com/question/13042571

#SPJ1

6 0
2 years ago
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