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3 years ago

Whoever solves this correctly will get the brainiest

Mathematics

1 answer:

Igoryamba3 years ago

4 0

Answer:

Step-by-step explanation:

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Does anyone understand geometry well?

sp2606 [1]

Answer:

I mean sure i guess

Step-by-step explanation:

How can i help?

8 0

3 years ago

If 30% of a number is 78 and 65% of the same number is 169, find 95% of that<br> number.

tigry1 [53]

Answer:

let say the number is x, then 30x÷100=78, x=260...from this we can calculate 95 percent of 260 which is equal to 247

6 0

2 years ago

find an equation of the tangent plane to the given parametric surface at the specified point. x = u v, y = 2u2, z = u − v; (2, 2

Alexxandr [17]

The surface is parameterized by

$\vec s(u,v) = x(u, v) \, \vec\imath + y(u, v) \, \vec\jmath + z(u, v)) \, \vec k$

and the normal to the surface is given by the cross product of the partial derivatives of $\vec s$ :

$\vec n = \dfrac{\partial \vec s}{\partial u} \times \dfrac{\partial \vec s}{\partial v}$

It looks like you're given

$\begin{cases}x(u, v) = u + v\\y(u, v) = 2u^2\\z(u, v) = u - v\end{cases}$

Then the normal vector is

$\vec n = \left(\vec\imath + 4u \, \vec\jmath + \vec k\right) \times \left(\vec \imath - \vec k\right) = -4u\,\vec\imath + 2 \,\vec\jmath - 4u\,\vec k$

Now, the point (2, 2, 0) corresponds to u and v such that

$\begin{cases}u + v = 2\\2u^2 = 2\\u - v = 0\end{cases}$

and solving gives $u = v = 1$ , so the normal vector at the point we care about is

$\vec n = -4\,\vec\imath+2\,\vec\jmath-4\,\vec k$

Then the equation of the tangent plane is

$\left(-4\,\vec\imath + 2\,\vec\jmath - 4\,\vec k\right) \cdot \left((x-2)\,\vec\imath + (y-2)\,\vec\jmath + (z-0)\,\vec k\right) = 0$

$-4(x-2) + 2(y-2) - 4z = 0$

$\boxed{2x - y + 2z = 2}$

6 0

2 years ago

Geometry question plz help

GarryVolchara [31]

Answer:if it’s a pretest just guess you don’t need to get it right

Step-by-step explanation:

5 0

3 years ago

1. Complete the square to form a perfect square trinomial. 8x + x² + __

olga_2 [115]

1. x² + 8x + 16
x² + 4x + 4x + 16
x(x) + x(4) + 4(x) + 4(4)
x(x + 4) + 4(x + 4)
(x + 4)(x + 4)
(x + 4)²
The answer is A.

2.   x² + 4x = 12
  x² + 4x + 4 = 12 + 4
  x² + 4x + 4 = 16
  x² + 2x + 2x + 4 = 16
x(x) + x(2) + 2(x) + 2(2) = 16
x(x + 2) + 2(x + 2) = 16
(x + 2)(x + 2) = 16
  (x + 2)² = 16
  √(x + 2)² = √16
x + 2 = ±4
  - 2 - 2
x = -2 ± 4
x = -2 + 4 or x = -2 - 4
x = 2   or x = -6
The answer is B.

3. x² + 9x + 4 = 0
  Δ = b² - 4ac
  Δ = (9)² - 4(1)(4)
  Δ = 81 - 4(4)
  Δ = 81 - 16
  Δ = 65
THe answer is C.

4. x² - 6x - 7 = 0
  Δ = b² - 4ac
  Δ = (-6)² - 4(1)(-7)
  Δ = 36 - 4(-7)
  Δ = 36 + 28
  Δ = 64
The answer is A.

7 0

4 years ago