Answer:
x=-3 or x=3/2
Step-by-step explanation:
We are given the following equation:
2x^2+5x-9=2x
We are asked to find the roots. That means just solve it for x.
2x^2+5x-9=2x
Subtract 2x on both sides:
2x^2+3x-9=0
Let's see if we can put this in factored form.
Compare
2x^2+3x-9=0
and
ax^2+bx+c=0.
a=2, b=3 , c=-9
We have to find two numbers that multiply to be ac and add up to be b.
ac=-18
b=3
What are two numbers that multiply to be -18 and add to be 3?
Say -3 and 6.
So we are going to factor 2x^2-3x+6x-9=0
The first two terms have a common factor of x.
The last two terms have a common factor of 3.
2x^2-3x+6x-9=0
x(2x-3)+3(2x-3)=0
Now we can factor the (x-3) out of those 2 terms there since they share that common factor:
(x+3)(2x-3)=0
(x+3)(2x-3)=0 implies x+3=0 or 2x-3=0.
So we must solve x+3=0 and 2x-3=0
x+3=0
Subtract 3 on both sides:
x=-3
2x-3=0
Add 3 on both sides:
2x=3
Divide both sides by 2:
x=3/2
The solutions are x=3 or x=-3/2
The product of (2j + 7)(2j - 7) is .
Given
The product mentally;
<h3>What is multiplication?</h3>
Multiplication is the process of calculating the product of two or more numbers.
The multiplication of numbers say, ‘a’ and ‘b’, is stated as ‘a’ multiplied by ‘b’.
The product of (2j + 7)(2j - 7) is given by
Hence, the product of (2j + 7)(2j - 7) is .
To know more about Multiplication click the link given below.
brainly.com/question/19943359
Answer:
What topic is this and which grade are u in?
Answer:
<h2>a. LM</h2><h2>b.
E</h2><h2>
c. No.</h2>
Step-by-step explanation:
a.
Two planes intersect in a line.
Here the intersecting line of the plane JKL and HGL is the line LM.
b.
As shown in the figure, the point which is coplanar to the points F, K and J is E.
c.
As per the given figure E, J and G are not in the same plane.
E and J can be lie in the same plane either EJK or EJN.
But point G is in EFG/ FGL/HGL.
Hence all the three points are not coplanar.
128 = 8d, because the product calls for multiplication to be performed.