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4 years ago

The formula for the volume of a come is V=1/3πr^2h. The radius, r, of the cone may be expressed as

1 answer:

6 0

Volume = (1/3) (π) (r²) (h)

Multiply each side by 3: 3V = (π) (r²) (h)

Divide each side by π : 3V/π = (r²) (h)

Divide each side by h : 3V / πh = r²

Take the square root
of each side: r = √ (3V/πh) .

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Last question I have

marta [7]

X=13

Hope this helps!

5 0

3 years ago

Determine the down payment for this vehicle: $28,900 truck at 24% down

WINSTONCH [101]

Based on the information given, the value of the down payment will be $6936.

<h3>Solving the percentage.</h3>

Based on the information given, the cost of the truck is $28900 and the down percentage given is 24%.

Therefore, the down payment that will be made will be:

= 24% × $28900

= 0.24 × $28900

= $6936

In conclusion, the correct option is $6936.

Learn more about percentages on:

brainly.com/question/24304697

3 0

2 years ago

What is the quotient when 4x3 + 2x + 7 is divided by x + 3?

Arte-miy333 [17]

Answer:

The quotient of this division is $(4x^2 -12x + 38)$ . The remainder here would be $-26$ .

Step-by-step explanation:

The numerator $4x^3 + 2x + 7$ is a polynomial about $x$ with degree $3$ .

The divisor $x + 3$ is a polynomial, also about $x$ , but with degree $1$ .

By the division algorithm, the quotient should be of degree $3 - 1 = 2$ , while the remainder shall be of degree $1 - 1 = 0$ (i.e., the remainder would be a constant.) Let the quotient be $a\,x^2 + b\, x + c$ with coefficients $a$ , $b$ , and $c$ .

$4x^3 + 2x + 7 = \left(a\,x^2 + b\, x + c\right)(x + 3)$ .

Start by finding the first coefficient of the quotient.

The degree-three term on the left-hand side is $4 x^3$ . On the right-hand side, that would be $a\, x^3$ . Hence $a = 4$ .

Now, given that $a = 4$ , rewrite the right-hand side:

$\begin{aligned}&\left(4\,x^2 + b\, x + c\right)(x + 3) \cr =& \left(4x^2 + (b\, x + c)\right)(x + 3) \cr =& 4x^2(x + 3) + (bx + c)(x + 3) \cr =& 4x^3 + 12x^2 + (bx + c)(x + 3)\end{aligned}$ .

Hence:

$4x^3 + 2x + 7 = 4x^3 + 12x^2 + (b\,x + c)(x + 3)$

Subtract $\left(4x^3 + 12x^2\right$ from both sides of the equation:

$-12x^2 + 2x + 7 = (b\,x + c)(x + 3)$ .

The term with a degree of two on the left-hand side has coefficient $(-12)$ . Since the only term on the right hand side with degree two would have coefficient $b$ , $b = -12$ .

Again, rewrite the right-hand side:

$\begin{aligned}&\left(-12 x + c\right)(x + 3) \cr =& \left(-12 x+ c\right)(x + 3) \cr =& (-12x)(x + 3) + c(x + 3) \cr =& -12x^2 -36x + (bx + c)(x + 3)\end{aligned}$ .