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3 years ago

A circle above has a radius of 6 cm. What is the area of the circle? Use = 3.14.

Mathematics

2 answers:

Ainat [17]3 years ago

8 0

Answer:

113.04

Step-by-step explanation:

formula for area is

pi times radius times radius

if the radius is 6,

do 6 times 6=36

36 times 3.14=113.04

zzz [600]3 years ago

4 0

113.04 will be ur answer

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Anvisha [2.4K]

2x2+xy+2y2=5Implicit differentiation yields4x+y+xy′+4y y′=0Solve for y′.

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3 years ago

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3 years ago

A manufacturer of potato chips would like to know whether its bag filling machine works correctly at the 410 gram setting. It is

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3 years ago

Solve <img src="https://tex.z-dn.net/?f=%5Csf%20%5Cdfrac%7B1%7D%7Bp%7D%20%2B%20%5Cdfrac%7B1%7D%7Bq%7D%20%2B%20%5Cdfrac%7B1%7D

Nostrana [21]

Answer:

$\displaystyle \begin{cases} \displaystyle {x} _{1} = - p \\ \displaystyle x _{2} = - q \end{cases}$

Step-by-step explanation:

we would like to solve the following equation for x:

$\displaystyle \frac{1}{p} + \frac{1}{q} + \frac{1}{x} = \frac{1}{p + q + x}$

to do so isolate $\frac{1}{x}$ to right hand side and change its sign which yields:

$\displaystyle \frac{1}{p} + \frac{1}{q} = \frac{1}{p + q + x} - \frac{1}{x}$

simplify Substraction:

$\displaystyle \frac{1}{p} + \frac{1}{q} = \frac{x - (q + p + x)}{x(p + q + x)}$

get rid of only x:

$\displaystyle \frac{1}{p} + \frac{1}{q} = \frac{ - (q + p )}{x(p + q + x)}$

simplify addition of the left hand side:

$\displaystyle \frac{q + p}{pq} = \frac{ - (q + p )}{x(p + q + x)}$

divide both sides by q+p Which yields:

$\displaystyle \frac{1}{pq} = \frac{ -1}{x(p + q + x)}$

cross multiplication:

$\displaystyle x(p + q + x) = - pq$

distribute:

$\displaystyle xp + xq + {x}^{2} = - pq$

isolate -pq to the left hand side and change its sign:

$\displaystyle xp + xq + {x}^{2} + pq = 0$

rearrange it to standard form:

$\displaystyle {x}^{2} + xp + xq + pq = 0$

now notice we end up with a quadratic equation therefore to solve so we can consider factoring method to use so

factor out x:

$\displaystyle x( {x}^{} + p ) + xq + pq = 0$

factor out q:

$\displaystyle x( {x}^{} + p ) +q (x + p)= 0$

group:

$\displaystyle ( {x}^{} + p ) (x + q)= 0$

by Zero product property we obtain:

$\displaystyle \begin{cases} \displaystyle {x}^{} + p = 0 \\ \displaystyle x + q= 0 \end{cases}$

cancel out p from the first equation and q from the second equation which yields:

$\displaystyle \begin{cases} \displaystyle {x}^{} = - p \\ \displaystyle x = - q \end{cases}$

and we are done!

3 0

3 years ago

Please help me this looks easy but I don’t understand it tho

Tems11 [23]

Let's call the unknown amount of money x

Betty spend 5/12 of her money (5/12)x and had 42 dollars left. Translated,

$x - \frac 5{12} x = 42$

Solving,

$x(1 - \frac 5{12}) = 42$

$\frac{7}{12} x = 42$

$x = \dfrac{12}{7} \cdot 42 = 72$

Answer: $72

4 0

3 years ago