Answer: 28x+42y=3
Step-by-step explanation:
Given: The point (x,y) is equidistant from the points
.
By distance formula the distance between
is
![D_1=\sqrt{(x-\frac{-1}{4})^2+(y-(-4))^2} \\=\sqrt{(x+\frac{1}{4})^2+(y+4)^2}](https://tex.z-dn.net/?f=D_1%3D%5Csqrt%7B%28x-%5Cfrac%7B-1%7D%7B4%7D%29%5E2%2B%28y-%28-4%29%29%5E2%7D%20%5C%5C%3D%5Csqrt%7B%28x%2B%5Cfrac%7B1%7D%7B4%7D%29%5E2%2B%28y%2B4%29%5E2%7D)
Similarly, the distance between
is
![D_2=\sqrt{(x-\frac{13}{4})^2+(y-(\frac{5}{4}))} \\=\sqrt{(x-\frac{13 }{4})^2+(y-\frac{5}{4})^2}](https://tex.z-dn.net/?f=D_2%3D%5Csqrt%7B%28x-%5Cfrac%7B13%7D%7B4%7D%29%5E2%2B%28y-%28%5Cfrac%7B5%7D%7B4%7D%29%29%7D%20%5C%5C%3D%5Csqrt%7B%28x-%5Cfrac%7B13%20%7D%7B4%7D%29%5E2%2B%28y-%5Cfrac%7B5%7D%7B4%7D%29%5E2%7D)
Since,
![D_1=D_2\\\\\Rightarrow\ \sqrt{(x+\frac{1}{4})^2+(y+4)^2}=\sqrt{(x-\frac{13}{4})^2+(y-\frac{5}{4})^2}\\\\\text{Squaring on the sides, we get}\\\Rightarrow(x+\frac{1}{4})^2+(y+4)^2=(x-\frac{13}{4})^2+(y-\frac{5}{4})^2\\\\\Rightarrow[x^2+\frac{1}{2}x+\frac{1}{16}]+y^2+8y+16=x^2-\frac{13}{2}x+\frac{169}{16}+y^2+\frac{25}{4}-\frac{5}{2}y\\\\\Rightarrow7x+\frac{21}{2}y=\frac{3}{4}\\\Rightarrow28x+42y=3](https://tex.z-dn.net/?f=D_1%3DD_2%5C%5C%5C%5C%5CRightarrow%5C%20%5Csqrt%7B%28x%2B%5Cfrac%7B1%7D%7B4%7D%29%5E2%2B%28y%2B4%29%5E2%7D%3D%5Csqrt%7B%28x-%5Cfrac%7B13%7D%7B4%7D%29%5E2%2B%28y-%5Cfrac%7B5%7D%7B4%7D%29%5E2%7D%5C%5C%5C%5C%5Ctext%7BSquaring%20on%20the%20sides%2C%20we%20get%7D%5C%5C%5CRightarrow%28x%2B%5Cfrac%7B1%7D%7B4%7D%29%5E2%2B%28y%2B4%29%5E2%3D%28x-%5Cfrac%7B13%7D%7B4%7D%29%5E2%2B%28y-%5Cfrac%7B5%7D%7B4%7D%29%5E2%5C%5C%5C%5C%5CRightarrow%5Bx%5E2%2B%5Cfrac%7B1%7D%7B2%7Dx%2B%5Cfrac%7B1%7D%7B16%7D%5D%2By%5E2%2B8y%2B16%3Dx%5E2-%5Cfrac%7B13%7D%7B2%7Dx%2B%5Cfrac%7B169%7D%7B16%7D%2By%5E2%2B%5Cfrac%7B25%7D%7B4%7D-%5Cfrac%7B5%7D%7B2%7Dy%5C%5C%5C%5C%5CRightarrow7x%2B%5Cfrac%7B21%7D%7B2%7Dy%3D%5Cfrac%7B3%7D%7B4%7D%5C%5C%5CRightarrow28x%2B42y%3D3)
Yeah, it is 5 and 1/10. and 5.01 is 5 and 1/100. so you are comparing 1/10 to 1/100. 1/10 is larger
In 2000 the median home price in a certain city was about $290,000, and from 2000 to 2006, home prices in the city rose in an average of about 11.3% per year. If prices continue to rise at that rate what would be the median home price would have been in 2018? Compare to the actual median price of about $400,000 in 2018. (median home price would be approximately ____ minion in 2018. Therefore 9:12
So, first you want to have 113 then you are going to want to divide it by pi or 3.14. After that, square it.
Your answer would be 6
The answer is 20 slices
8/0.4 = 20