Part B: A triangle has vertices A (-2, 3), B (0, 0), and C (1, 2). What are the coordinates of the vertices if the original tria
1 answer:
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Answer:
A. x equals 5 plus or minus the square root of thirty-three all over 2
Step-by-step explanation:
Let's move all the terms to one side:
Now, we want to use the quadratic formula, which states that for a quadratic equation of the form , the roots can be found with the equation:
or
.
Here, a = 1, b = -5, and c = -2, so plug these in:
OR
Thus, the answer is A.
Hope this helps!
the length of the side of this square is cm
Answer:
Solutions Given:
let diagonal of square be AC: 8 cm
let each side be a.
As diagonal bisect square.
let it forms right angled triangle ABC .
Where diagonal AC is hypotenuse and a is their opposite side and base.
By using Pythagoras law
hypotenuse ²=opposite side²+base side²
8²=a²+a²
64=2a²
a²=
a²=32
doing square root on both side
a=±
a=±2*2
Since side of square is always positive so
a=4 or 5.65 cm
