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allochka39001 [22]
3 years ago
11

Part B: A triangle has vertices A (-2, 3), B (0, 0), and C (1, 2). What are the coordinates of the vertices if the original tria

ngle is dilated by a scale factor of 3 and then reflected over the x-axis?
Mathematics
1 answer:
Black_prince [1.1K]3 years ago
5 0

Answer:

(-6,-9) , (0,0) and (3,-6)

Step-by-step explanation:

Here, we want to find new coordinates after dilating by 3 and reflecting over x-axis

By dilating by a factor of 3, we multiply each term by 3

We have the following;

A’(-6,9) B’(0,0) and C’ (3,6)

Now if we want to reflect the point (x,y) over x-axis, what we shall have is (x,-y)

So the vertices will be as follows;

(-6,-9) , (0,0) and (3,-6)

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The gradiant y=2x³-5x+1 at point (2,7)​
olga2289 [7]

Given:

The equation of the curve is:

y=2x^3-5x+1

To find:

The gradient (slope) of the given curve at point (2,7).

Solution:

We have,

y=2x^3-5x+1

Differentiate the given equation with respect to x.

y=2(3x^2)-5(1)+(0)

y'=6x^2-5

Now we need to find the value of this derivative at (2,7).

y'_{(2,7)}=6(2)^2-5

y'_{(2,7)}=6(4)-5

y'_{(2,7)}=24-5

y'_{(2,7)}=19

Therefore, the gradient (slope) of the given curve at point (2,7) is 19.

8 0
3 years ago
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Step-by-step explanation:

Solution

According to remainder theorem, when f(x) is divided by (x+2), Remainder =f(−2)

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f(−2)=5(−2)3+2(−2)2−6(−2)+12

=5×−8+2×4+12+12

=−40+32=−8

∴ Remainder=−8

5 0
3 years ago
Use the rule y=-x+7to fill in the blank (1,y) is on the graph,then y=
Anon25 [30]
Y = 6 because - ( 1 ) + 7 = 6
6 0
3 years ago
Read 2 more answers
7. Is a triangle with side lengths 9, 18, 7 a right triangle, an acute triangle, or
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I think the answer is Obtuse
8 0
3 years ago
If x^3+y^3−12xy+64=0, what is the value of x+y?
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Answer:

I don't know

Step-by-step explanation:

I don't really know but if you want help with math questions try this website called wolfram alpha. It's great

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