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allochka39001 [22]
2 years ago
11

Part B: A triangle has vertices A (-2, 3), B (0, 0), and C (1, 2). What are the coordinates of the vertices if the original tria

ngle is dilated by a scale factor of 3 and then reflected over the x-axis?
Mathematics
1 answer:
Black_prince [1.1K]2 years ago
5 0

Answer:

(-6,-9) , (0,0) and (3,-6)

Step-by-step explanation:

Here, we want to find new coordinates after dilating by 3 and reflecting over x-axis

By dilating by a factor of 3, we multiply each term by 3

We have the following;

A’(-6,9) B’(0,0) and C’ (3,6)

Now if we want to reflect the point (x,y) over x-axis, what we shall have is (x,-y)

So the vertices will be as follows;

(-6,-9) , (0,0) and (3,-6)

You might be interested in
A particle moves according to a law of motion s = f(t), t ? 0, where t is measured in seconds and s in feet.
Usimov [2.4K]

Answer:

a) \frac{ds}{dt}= v(t) = 3t^2 -18t +15

b) v(t=3) = 3(3)^2 -18(3) +15=-12

c) t =1s, t=5s

d)  [0,1) \cup (5,\infty)

e) D = [1 -9 +15] +[(5^3 -9* (5^2)+ 15*5)-(1-9+15)]+ [(6^3 -9(6)^2 +15*6)-(5^3 -9(5)^2 +15*5)] =7+ |32|+7 =46

And we take the absolute value on the middle integral because the distance can't be negative.

f) a(t) = \frac{dv}{dt}= 6t -18

g) The particle is speeding up (1,3) \cup (5,\infty)

And would be slowing down from [0,1) \cup (3,5)

Step-by-step explanation:

For this case we have the following function given:

f(t) = s = t^3 -9t^2 +15 t

Part a: Find the velocity at time t.

For this case we just need to take the derivate of the position function respect to t like this:

\frac{ds}{dt}= v(t) = 3t^2 -18t +15

Part b: What is the velocity after 3 s?

For this case we just need to replace t=3 s into the velocity equation and we got:

v(t=3) = 3(3)^2 -18(3) +15=-12

Part c: When is the particle at rest?

The particle would be at rest when the velocity would be 0 so we need to solve the following equation:

3t^2 -18 t +15 =0

We can divide both sides of the equation by 3 and we got:

t^2 -6t +5=0

And if we factorize we need to find two numbers that added gives -6 and multiplied 5, so we got:

(t-5)*(t-1) =0

And for this case we got t =1s, t=5s

Part d: When is the particle moving in the positive direction? (Enter your answer in interval notation.)

For this case the particle is moving in the positive direction when the velocity is higher than 0:

t^2 -6t +5 >0

(t-5) *(t-1)>0

So then the intervals positive are [0,1) \cup (5,\infty)

Part e: Find the total distance traveled during the first 6 s.

We can calculate the total distance with the following integral:

D= \int_{0}^1 3t^2 -18t +15 dt + |\int_{1}^5 3t^2 -18t +15 dt| +\int_{5}^6 3t^2 -18t +15 dt= t^3 -9t^2 +15 t \Big|_0^1 + t^3 -9t^2 +15 t \Big|_1^5 + t^3 -9t^2 +15 t \Big|_5^6

And if we replace we got:

D = [1 -9 +15] +[(5^3 -9* (5^2)+ 15*5)-(1-9+15)]+ [(6^3 -9(6)^2 +15*6)-(5^3 -9(5)^2 +15*5)] =7+ |32|+7 =46

And we take the absolute value on the middle integral because the distance can't be negative.

Part f: Find the acceleration at time t.

For this case we ust need to take the derivate of the velocity respect to the time like this:

a(t) = \frac{dv}{dt}= 6t -18

Part g and h

The particle is speeding up (1,3) \cup (5,\infty)

And would be slowing down from [0,1) \cup (3,5)

5 0
3 years ago
The length of a rectangular garden is 7ft more than the width. The perimeter is 50 ft. Find the width.
Vilka [71]
<h2>Answer:</h2>

<em>W=9</em>

<h2>Step-by-step explanation:</h2>

<em>Hope this helps, here is the answer please mark Brainliest.</em>

8 0
2 years ago
Need help from 7-9 pls
expeople1 [14]

Answer:

b 5 a 6 b 7

Step-by-step explanation:

5 0
3 years ago
Circle D was dialated to form circle D'. The diameter of circle D is 5 units and the diameter of circle D' is 15 units. What is
Sphinxa [80]

Answer:

Let A1 be original area

A2 dilated Area

A1=pi*d^2/4

=3.143*5^2/4

A1=19.63 unit square

A2= 3.143*15/4

A2=176.74 unit square

A2 is 9 times greater than A1

Hence the answer is B

Step-by-step explanation:

3 0
2 years ago
Which expressions have an estimated quotient of 200? Select all that apply.
marta [7]

Answer:

E

                                       

                                             

Hope it helps!                    

3 0
2 years ago
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