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trasher [3.6K]
3 years ago
6

Ball thrown straight up

Mathematics
1 answer:
Tema [17]3 years ago
6 0

Answer:

x = 2

Step-by-step explanation:

H(x) = 64x - 16x²

<u>Find the value of x when the ball reaches its maximum height.</u>

<u />

Since the largest degree in this equation is two, this function represents a parabola. We can find the maximum height of the ball at the vertex of the quadratic.

In H(x) = 64x - 16x², rearrange the powers from greatest to least:

  • a = -16
  • b = 64
  • c = 0

Vertex: [-b/2a, f(-b/2a)]

Substitute a and b into the x-value of the vertex: -b/2a.

  • -(64)/2·(-16)
  • -64/-32
  • 2

The vertex of the parabola is at x = 2, with a maximum height of H(2).

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