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Aloiza [94]
2 years ago
9

What fraction of the number are prime numbers from 2 to 14​

Mathematics
1 answer:
frez [133]2 years ago
5 0

Answer:

i hope you got it.

plz mark brainliest.

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CAN SOMEONE EXPLAIN AND MAYBE SHOW ME STEP BY STEP WHY THE ANSWER IS 75degrees. HURRY 50 points and brainiest!!!
KonstantinChe [14]

Answer:

75 degrees, we know that already so look below lol.

Step-by-step explanation:

This triangle is an isosceles triangle, LP is equivalent to LQ, and angles LQP and LPQ are also equivalent. We understand that PLQ is equal to 30 degrees, since its complementary to triangle LQM.

180 - 30 = 150

150/2 = 75.

<em>Have a nice day, fam. Spread The Love. Thanks for the opportunity.</em>

3 0
2 years ago
Read 2 more answers
Find a formula for the sun S of any three consecutive odd number?​
bixtya [17]

Answer:

Let first no. be x

Therefore,

2nd no. is x+1

Third no. is x+2

<em><u>SUM</u></em><em><u> </u></em><em><u>OF</u></em><em><u> </u></em><em><u>NO</u></em><em><u>.</u></em><em><u>'</u></em><em><u>s</u></em><em><u>=</u></em><em><u>x</u></em><em><u>+</u></em><em><u>x</u></em><em><u>+</u></em><em><u>1</u></em><em><u>+</u></em><em><u>x</u></em><em><u>+</u></em><em><u>2</u></em>

<em><u>S</u></em><em><u>=</u></em><em><u>3x</u></em><em><u>+</u></em><em><u>3</u></em>

<em><u>S</u></em><em><u>=</u></em><em><u>3</u></em><em><u>(</u></em><em><u>x</u></em><em><u>+</u></em><em><u>1</u></em><em><u>)</u></em>

8 0
3 years ago
Read 2 more answers
Consider parallelogram VWXY below.
nirvana33 [79]

Answer:

  • 56°, 84°, 3 units

Step-by-step explanation:

<u>Properties of a parallelogram</u>

  • Two adjacent angles are supplementary
  • Opposite angles are congruent
  • Opposite sides are parallel and congruent

Use the properties to find the required parameters

1) <u>Find m∠YXV</u>

  • m∠YXV + m∠VXW + m∠VWX = 180°
  • m∠YXV + 40° + 84° = 180°
  • m∠YXV = 180° - 124°
  • m∠YXV = 56°

2) <u>Find m∠Y</u>

  • m∠Y = m∠W = 84°

3) <u>Find x</u>

  • 2x = 6
  • x = 6/2
  • x = 3
4 0
2 years ago
Read 2 more answers
A 100 gallon tank initially contains 100 gallons of sugar water at a concentration of 0.25 pounds of sugar per gallon suppose th
Vsevolod [243]

At the start, the tank contains

(0.25 lb/gal) * (100 gal) = 25 lb

of sugar. Let S(t) be the amount of sugar in the tank at time t. Then S(0)=25.

Sugar is added to the tank at a rate of <em>P</em> lb/min, and removed at a rate of

\left(1\frac{\rm gal}{\rm min}\right)\left(\dfrac{S(t)}{100}\dfrac{\rm lb}{\rm gal}\right)=\dfrac{S(t)}{100}\dfrac{\rm lb}{\rm min}

and so the amount of sugar in the tank changes at a net rate according to the separable differential equation,

\dfrac{\mathrm dS}{\mathrm dt}=P-\dfrac S{100}

Separate variables, integrate, and solve for <em>S</em>.

\dfrac{\mathrm dS}{P-\frac S{100}}=\mathrm dt

\displaystyle\int\dfrac{\mathrm dS}{P-\frac S{100}}=\int\mathrm dt

-100\ln\left|P-\dfrac S{100}\right|=t+C

\ln\left|P-\dfrac S{100}\right|=-100t-100C=C-100t

P-\dfrac S{100}=e^{C-100t}=e^Ce^{-100t}=Ce^{-100t}

\dfrac S{100}=P-Ce^{-100t}

S(t)=100P-100Ce^{-100t}=100P-Ce^{-100t}

Use the initial value to solve for <em>C</em> :

S(0)=25\implies 25=100P-C\implies C=100P-25

\implies S(t)=100P-(100P-25)e^{-100t}

The solution is being drained at a constant rate of 1 gal/min; there will be 5 gal of solution remaining after time

1000\,\mathrm{gal}+\left(-1\dfrac{\rm gal}{\rm min}\right)t=5\,\mathrm{gal}\implies t=995\,\mathrm{min}

has passed. At this time, we want the tank to contain

(0.5 lb/gal) * (5 gal) = 2.5 lb

of sugar, so we pick <em>P</em> such that

S(995)=100P-(100P-25)e^{-99,500}=2.5\implies\boxed{P\approx0.025}

5 0
2 years ago
Which of the following is NOT true? Question 19 options: (3x2y5)3=27x6y15 (1000x12y20z−3)0=1 52‾‾√3=523 42×43= 165
bixtya [17]

Answer:


Step-by-step explanation:

Lets try to simplify each to check which one is incorrect so it will be NOT true

first one is :

distribute the exponent so :

(3x^2y^5)^3 =3^3x^{2*3}y^{5*3}

27x^6y^{15} CORRECT

Second one is :

(1000x^{12}y^{20}z^{-30})^{0} =1

CORRECT because anything raised to exponent 0 is 1 .

Last one is :

4^2 *4^3 = 4^{2+3}\\=4^{6}\\=(4)^{2*3}\\=16^{3}

so Last is<em> INCORRECT</em>



5 0
3 years ago
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