Very Short Answer Type Question (any 9)
1 answer:
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Answer:
The program in Python is as follows:
import collections
from collections import Counter
from itertools import groupby
import statistics
str_input = input("Enter a series of numbers separated by space: ")
num_input = str_input.split(" ")
numList = []
for num in num_input:
if(num.lstrip('-').isdigit()):
if num[0] == "-" or int(num)>10:
print(num," is out of bound - rejecting")
else:
print(num," is valid - accepting")
numList.append(int(num))
else:
print(num," is not a number")
print("Largest number: ",max(numList))
print("Smallest number: ",min(numList))
print("Range: ",(max(numList) - min(numList)))
print("Mode: ",end = " ")
freqs = groupby(Counter(numList).most_common(), lambda x:x[1])
print([val for val,count in next(freqs)[1]])
count_freq = {}
count_freq = collections.Counter(numList)
for item in count_freq:
print(item, end = " ")
lent= int(count_freq[item])
for i in range(lent):
print("#",end=" ")
print()
Explanation:
See attachment for program source file where comments are used as explanation. (Lines that begin with # are comments)
The frequency polygon is printed using #'s to represent the frequency of each list element
Answer:
=IF(B2>=23,"Yes","No")
Explanation:
Given
Name = Kay Colbert
The Name column can't be used to determine the eligibility of a student to the transport.
What is needed is the corresponding age column of Kay's age.
Assume that the age column is B2 and the result column is C2 (See Attachment)
Enter the following in C2
=IF(B2>=23,"Yes","No")
This will return "Yes" without the quotes in cell C2 if B2 is greater than 23
Else, it'll return "No" without the quotes.
To drag the formula to other column, follow the instructions below
Select cell C2.
Rest your cursor in the lower-right corner so that it turns into a plus sign (+), like this:
Drag the fill handle downwards
